# Recent content by Hypnos_16

1. ### Chemistry Classify each solid as a covalent, ionic, metallic, or molecular solid.

1. Homework Statement As the title would lead you to believe I have to classify each solid as a covalent, ionic, metallic, or molecular solid. These are the given solids Calcium Fluoride Rhombic Sulfur Frozen Ethanol Pure Calcium 2. Homework Equations n / a 3. The...
2. ### Determine whether the series is convergent or divergent

1. Homework Statement I have to find whether the following is Convergent or Divergent ∑ from n = 1 to infinity 2 / n(2n + 2)^(1/4) Actually it's the fourth root, this is just easier to write. 2. Homework Equations According to the front of the sheet it's a quiz on P-Series and Integral...
3. ### Computer Science Simple Animations

1. Homework Statement Create a class called, ThreeObjectAnimation, that creates a graphic animation with three animation object. The ThreeObjectAnimation class should move three objects around the frame, either randomly, or following a fixed pattern. The movements should occur every 250...
4. ### Find the Current at a Certain Point

Sorry about the Picture thing, so, if i have two batteries in the same loop, do i add together their voltage?
5. ### Find the Current at a Certain Point

1. Homework Statement For the circuit in the diagram below, R1 = 34.0 Ω, R2 = 20.0 Ω, ε1 = 8.50 V, ε2 = 10.5 V and ε3 = 10.5 V are connected as shown in the figure. http://loncapa.physics.mun.ca/res/mun/cdeacon/capalibrary/Graphics/Gtype1021/A5Problem30.gif What is the value of current I1...
6. ### Chemistry Calorimetry Question Find Final Temp.

1. Homework Statement 10.11g of CaO (molar mass = 56.08 g / mol) is dropped into a styrofoam coffee cup containing 157.0 g of H2O at 25.0ºC. If the following reaction occurs, calculate the final temperature of the water assuming that the cup acts as a perfect insulator. (Assume that the...
7. ### Magnetic Field in a Cylindrical Conductor

Not to worry, i got the answer. I was using the wrong equation. For values of Magnetic Field inside the given radius the equation is B = µIr / 2πa^2 B = (4π x 10^-7)(2.17)(0.01245) / 2π(0.0249^2) B = 8.71e-6 T In case anyone else had the same or similar problems.
8. ### Magnetic Field in a Cylindrical Conductor

1. Homework Statement A cylindrical conductor of radius R = 2.49 cm carries a current of I = 2.17 A along its length; this current is uniformly distributed throughout the cross-section of the conductor. Calculate the magnetic field midway along the radius of the wire (that is, at r = R/2)...
9. ### Using Boolean Algebra to Prove Equations

1. Homework Statement There should be lines of some values to imply the "Not" form of them, however to make it easier, i'll just use the ¬ Symbol (a) Let x, y be elements of a Boolean algebra. Prove from the axioms that (x · y) + x = x. (b) Prove from the axioms of Boolean algebra that...
10. ### Magnitude of Electric Field from an Atom

-1.67e-6 = [k(q) / r2] * [4πr2] -1.67e-6 / [4πr2] = [k(q) / r2] -1.67e-6[r2] / [4πr2] = k(q) -1.67e-6 / 4π = k(q) -1.33e-7 = k(q) q = -1.33e-7 / 8.99e9 q = -1.48e-17 N/C
11. ### Magnitude of Electric Field from an Atom

Sure, but what will that do? Gauss's Law = EA = (3.16e11)(4π(6.5e-10)2) = 1.67e-6
12. ### Magnitude of Electric Field from an Atom

1. Homework Statement The neutral neptunium atom has 93 electrons. What is the magnitude of its electric field at a distance of 6.5x10-10 m from the nucleus? Hint: The number of protons in a nucleus is equal to the number of electrons in the neutral atom. q = 1.6e-19 * 93 =...
13. ### Electric Field Between two Charges Equals 0

I'm assuming that the 3 and the 2 that you're using are the charges? Then why not add the Negative to the two? or is it irrelevant in this case E3 = 3/(x)^2 E2 = 2/(x-d)^2 3.17 / x2 = 2.19 / (x - d)2 √(2.19 / 3.17) = (x - d) / x √(2.19 / 3.17) = (1) - (d / x) 0.8311 = 1 - (d / x)...
14. ### Electric Field Between two Charges Equals 0

Where did you get the 0.4617 From? Everything else i can see.
15. ### Electric Field Between two Charges Equals 0

q1 / q2 = (x - d)2 / (x)2 3.17 / -2.19 = (x - d)2 / (x)2 √[3.17 / -2.19 = (x - d)2 / (x)2] 1.20 = (x - d) / x 1.20x = x - d 1.20(0.0365) = (0.0365 - d) 0.0438 = 0.0365 - d -0.0438 = -0.0365 + d d = -0.0073 m => -0.73 cm Something like that then?