Recent content by Hypnos_16

Homework Statement As the title would lead you to believe I have to classify each solid as a covalent, ionic, metallic, or molecular solid. These are the given solids Calcium Fluoride Rhombic Sulfur Frozen Ethanol Pure Calcium Homework Equations n / a The Attempt at a...

Homework Statement I have to find whether the following is Convergent or Divergent ∑ from n = 1 to infinity 2 / n(2n + 2)^(1/4) Actually it's the fourth root, this is just easier to write. Homework Equations According to the front of the sheet it's a quiz on P-Series and Integral Test I'm...

Sorry about the Picture thing, so, if i have two batteries in the same loop, do i add together their voltage?

Homework Statement For the circuit in the diagram below, R1 = 34.0 Ω, R2 = 20.0 Ω, ε1 = 8.50 V, ε2 = 10.5 V and ε3 = 10.5 V are connected as shown in the figure. http://loncapa.physics.mun.ca/res/mun/cdeacon/capalibrary/Graphics/Gtype1021/A5Problem30.gif What is the value of current I1...

Homework Statement 10.11g of CaO (molar mass = 56.08 g / mol) is dropped into a styrofoam coffee cup containing 157.0 g of H2O at 25.0ºC. If the following reaction occurs, calculate the final temperature of the water assuming that the cup acts as a perfect insulator. (Assume that the...

Not to worry, i got the answer. I was using the wrong equation. For values of Magnetic Field inside the given radius the equation is B = µIr / 2πa^2 B = (4π x 10^-7)(2.17)(0.01245) / 2π(0.0249^2) B = 8.71e-6 T In case anyone else had the same or similar problems.

Homework Statement A cylindrical conductor of radius R = 2.49 cm carries a current of I = 2.17 A along its length; this current is uniformly distributed throughout the cross-section of the conductor. Calculate the magnetic field midway along the radius of the wire (that is, at r = R/2)...

Homework Statement There should be lines of some values to imply the "Not" form of them, however to make it easier, i'll just use the ¬ Symbol (a) Let x, y be elements of a Boolean algebra. Prove from the axioms that (x · y) + x = x. (b) Prove from the axioms of Boolean algebra that x...

-1.67e-6 = [k(q) / r2] * [4πr2] -1.67e-6 / [4πr2] = [k(q) / r2] -1.67e-6[r2] / [4πr2] = k(q) -1.67e-6 / 4π = k(q) -1.33e-7 = k(q) q = -1.33e-7 / 8.99e9 q = -1.48e-17 N/C

Sure, but what will that do? Gauss's Law = EA = (3.16e11)(4π(6.5e-10)2) = 1.67e-6

Homework Statement The neutral neptunium atom has 93 electrons. What is the magnitude of its electric field at a distance of 6.5x10-10 m from the nucleus? Hint: The number of protons in a nucleus is equal to the number of electrons in the neutral atom. q = 1.6e-19 * 93 = 1.48e-17...

I'm assuming that the 3 and the 2 that you're using are the charges? Then why not add the Negative to the two? or is it irrelevant in this case E3 = 3/(x)^2 E2 = 2/(x-d)^2 3.17 / x2 = 2.19 / (x - d)2 √(2.19 / 3.17) = (x - d) / x √(2.19 / 3.17) = (1) - (d / x) 0.8311 = 1 - (d / x)...

Where did you get the 0.4617 From? Everything else i can see.

q1 / q2 = (x - d)2 / (x)2 3.17 / -2.19 = (x - d)2 / (x)2 √[3.17 / -2.19 = (x - d)2 / (x)2] 1.20 = (x - d) / x 1.20x = x - d 1.20(0.0365) = (0.0365 - d) 0.0438 = 0.0365 - d -0.0438 = -0.0365 + d d = -0.0073 m => -0.73 cm Something like that then?

Alright, so we know that it's to the right, I don't see how this is helping solving the problem i have.