Recent content by IDK10

Just redid the equation and got values ten times smaller than before, so its 4.02192 g dm-3 for the 25 cm3 for the acid used. So, x25 now?

If by buoyancy you mean upthrust, then no, a previous part of the question says it is neglibible. So its just F = W.

1. The problem statement, "all variables and given/known data A solution of nitric acid, HNO3, of concentration 100 g dm-3, can be used to artificially age wood. A sample of nitric acid was tested by pipetting 10.00 cm3 of the acid into a 250 cm3 volumetric flask and filled up with deionised...

Homework Statement Using the viscosity of air as 1.8x10-5Pa s, and the density of water as 1x103kg m-3, find the radius of a raindrop traveling at a terminal velocity of 7.05ms-1. Assume Stokes law can be used. The problem is finding the density of air, I could use F = 6rvπη but I don't know...

First of all, I didn't know where to put this in general math or differential equations. Let's start with the basic, x/0 = α. Where α is every number and decimal number from -∞ to +∞, by rearranging, we get x = 0α, x= 0, therefore only 0/0 = α. Now, we can integrate this with graphs. Take the...

Had shift on for too long, the o in 'NO' was meant to be lower case.

NO, was just kind of quickly typing that, sorry.

Greater, so...: In series: The brightest bulb has less resistance, greatest voltage and same current as the dimmest bulb. In parallel: The brightest bulb has less resistance, greater current and the same voltage as the dimmer bulb?

In terms of your question, the total voltage drops in the two bulbs = the emf of the cell, and the current flowing through a series circuit is constant. But what I mean is, what if the two bulbs are of different brightness, and are in series, what would be an easy way to visualise which one has...

There are two circuits, each consist of a cell and two bulbs, in one circuit they are in parallel, and in the other they are in series. What's the best way to remember which lamp has the greatest pd, current and resistance when one bulb is brighter than the other in the series and parallel circuit?

Sodium chlorate(III): 1+3-2O=0 -2O=-4 O=2 NaClO2 Sodium chlorate(V): 1+5-2O=0 -2O=-6 O=3 NaClO3

While I was away, amd therefore didn't see your reply, I was thinking and I think i got it: 1 + 1 -2O = 0 -2O = -2 O = 1 NaClO?

I'm not sure, I have to find the formula just from the name. I know sodium chlorate(v) has 3.

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For sodium chlorate(I) Na would be +1 Cl would be +1 and O would be -2 1 + 1 - 3(2) = -4 (what would I do with this?) Or Na + 1 -6 = 0 Na = 5 (?) For sodium chlorate(V) Na would be +1 Cl would be +5 and O would be -2 1 + 5 - 3(-2) = 0 NaClO3