B How to remember what happens to I, V and R in a circuit?

AI Thread Summary
In circuits with bulbs in series and parallel, understanding voltage, current, and resistance is essential for determining brightness. Kirchhoff's Voltage Law (KVL) indicates that voltage is shared in series, while Kirchhoff's Current Law (KCL) shows that current is shared in parallel. In a series circuit, the brightest bulb has the least resistance and the highest voltage, while the current remains constant across both bulbs. Conversely, in parallel, the brightest bulb has the least resistance and the greatest current, with voltage being the same for both. Analyzing these relationships helps clarify how to visualize and remember the behavior of bulbs in different circuit configurations.
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There are two circuits, each consist of a cell and two bulbs, in one circuit they are in parallel, and in the other they are in series. What's the best way to remember which lamp has the greatest pd, current and resistance when one bulb is brighter than the other in the series and parallel circuit?
 
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I'm not too keen on the idea of rote learning stuff like this. There are some very straightforward 'Laws' which you can use and you can guarantee they will give you the right answers.
Firstly, we all know that V=I/R (and the other two combinations) and that Power = VI. Then:
Kirchoff's Voltage Law (KVL) says that the total voltage drop around a series circuit (loop) is zero. That means that the total supplied volts adds up to the total of voltage drops across all the other elements. (aka Volts are 'shared' in series)
Kirchoff's Current Law (KCL) says that the total current into a node (connection point for two or more components) is Zero. (aka Current is shared in parallel)
So, using KVL, what can you say about the volts across the two bulbs and the Cell voltage in a series circuit? What can you say about the Current flowing through the series circuit?
Work it out with ant particular example you can think of - then another one. That will show you the trend.
 
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sophiecentaur said:
I'm not too keen on the idea of rote learning stuff like this. There are some very straightforward 'Laws' which you can use and you can guarantee they will give you the right answers.
Firstly, we all know that V=I/R (and the other two combinations) and that Power = VI. Then:
Kirchoff's Voltage Law (KVL) says that the total voltage drop around a series circuit (loop) is zero. That means that the total supplied volts adds up to the total of voltage drops across all the other elements. (aka Volts are 'shared' in series)
Kirchoff's Current Law (KCL) says that the total current into a node (connection point for two or more components) is Zero. (aka Current is shared in parallel)
So, using KVL, what can you say about the volts across the two bulbs and the Cell voltage in a series circuit? What can you say about the Current flowing through the series circuit?
Work it out with ant particular example you can think of - then another one. That will show you the trend.
In terms of your question, the total voltage drops in the two bulbs = the emf of the cell, and the current flowing through a series circuit is constant.

But what I mean is, what if the two bulbs are of different brightness, and are in series, what would be an easy way to visualise which one has the highest current and voltage, and the same for in parallel?
 
Brightness is related to the power dissipated: ##P=I_{through}V_{across}##.
As @sophiecentaur , asks
in series, how are the currents through each resistor related?
Then, if one bulb is brighter than the other, what can you say about the voltage across the brighter bulb?
 
robphy said:
Brightness is related to the power dissipated: ##P=I_{through}V_{across}##.
As @sophiecentaur , asks
in series, how are the currents through each resistor related?
Then, if one bulb is brighter than the other, what can you say about the voltage across the brighter bulb?
Greater, so...:
In series:
The brightest bulb has less resistance, greatest voltage and same current as the dimmest bulb.
In parallel:
The brightest bulb has less resistance, greater current and the same voltage as the dimmer bulb?
 
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IDK10 said:
In series:
The brightest bulb has less resistance, greatest voltage and same current as the dimmest bulb.
In parallel:
The brightest bulb has less resistance, greater current and the same voltage as the dimmer bulb?
Power dissipated in the bulb will be I2Rbulb (this comes from P=Vacross*Ithrough).

Use this expression in series and parallel circuits and see in which case which bulb should glow brighter than the other.
 
IDK10 said:
in series, what would be an easy way to visualise which one has the highest current and voltage
Hang on there! Will they have different currents?
 
IDK10 said:
But what I mean is, what if the two bulbs are of different brightness, and are in series, what would be an easy way to visualise which one has the highest current and voltage

in the same post you stated the answer to this Q ...

IDK10 said:
the total voltage drops in the two bulbs = the emf of the cell, and the current flowing through a series circuit is constant.

and again in a subsequent post

IDK10 said:
In series:
The brightest bulb has less resistance, greatest voltage and same current as the dimmest bulb.
Dave
 
IDK10 said:
In series: The brightest bulb has less resistance, greatest voltage and same current as the dimmest bulb.
How can that be true? If the bulb is brighter then it is dissipating more power. For the same current (series circuit), the VI must be greater, which means the V must be higher so R (=V/I) must be higher. The higher resistance bulb 'steals' more of a share of the volts.
Stick to the logic and analyse your 'summing up' statements to see whether or not they can be true.
 
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sophiecentaur said:
Hang on there! Will they have different currents?
NO, was just kind of quickly typing that, sorry.
 
  • #11
IDK10 said:
NO, was just kind of quickly typing that, sorry.
Had shift on for too long, the o in 'NO' was meant to be lower case.
 
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