Recent content by IonizingJai

That is, for Supernode -1,3 (12V branch) , we do Nodal Analysis and we have (V2-V3)/2 , over the 2 ohm branch. But this current is not included in the Equation 1 in the solution I have attached(Which is my only source to cross check answers/solution right now.) Is the solution wrong? Thanks...

Oh no, I just realized I have made so many mistakes while writing out the reply. Correct. EDIT: the condition is ##\frac {1+x} {1+y} \gt 0 ##. Still, not fully clear on inequality/condition part.

Sorry, I made the mistake in OP and it went unnoticed even after I gave it a check, I find writing LaTeX code difficult, apologies for any time waste, my mistake might have caused. I will edit the OP, okay? Looks like there is no option to edit the post. so, I will post it here: EDIT : the...

Thanks to all who replied. Here's what I did, as kuruman suggested, First, covert given expression to $$\frac {x} {y} = -\frac{\sqrt{1+x}}{\sqrt{1+y}} $$ Then, squaring b/s we get, ##\frac {x^2} {y^2} = -\frac{1+x}{1+y}##, manupulating expression to get , ## x+ y +xy = 0##. $$ y =...

Homework Statement If ##x\sqrt{1+y} + y\sqrt{1+x } = 0##, then prove that ##\frac {dy} {dx} = \frac {-1}{(x-1)^2}##. 2.Relevant Equations: $$ \frac {dy} {dx} = - \frac {\left (\frac {\partial f}{\partial x} \right)} {\left( \frac {\partial f} {\partial y} \right)}.$$ 3...

That's quite right ! i think i was way too lost in wondering why the author in the book wrote the equations the way he did, and i should have tried your line of approach(which i initially was saying saying should be correct) and didn't proceed further to subtract the equations of Va-Vb...

I understand that, but that is not what I'm confused about, I'm confused about what i have mentioned in my OP, i.e In those attached images, i think the the potential at shell A(1st equation i.e Va =) and B (second equation Vb =) must be the sum of potential due to shell A and B at the required...

Homework Statement :[/B] This is isn't exactly a problem,but actually something i don't understand in the book i was following, so there this art. about 'Principle of a Generator', whose description is given as, " A generator is an instrument for producing high voltages in the MeV range. Its...

Thanks for replying vela, but if you check my solution at post NO , #5 , i have done exactly what you said , i have only left the steps in which i had to cancel many things out and expand and stuff. if you check it you will find that i have done. and i don't get what Mark44 is implying , the...

Sorry , but i don't get what are you guys implying ?

##A\sqrt{2}##

Alright , then that means i am wrong. So , if the question is correct , it ask for the value of the angle between the two forces so that the Resultant maybe ## \sqrt{(A^2+B^2)}##. Mark44 : as you said i should simplify the but HallsofIvy already showed its not possible to arrive on the...

Yeah , i never approached the problem this way, sorry. Also i found another way : Let the given forces be ##\vec F_1=\vec A+\vec B## and ##\vec F_2=\vec A-\vec B## . Now, Resultant vector ##\vec F_1 + \vec F_2 = (\vec A+\vec B) + (\vec A-\vec B)## Magnitude of Resultant: ##|\vec F_1 + \vec...

Question: At what angles must be the two forces ##\vec A+\vec B## and ##\vec A-\vec B## act so that the resultant may be : $$\sqrt{ A^2+B^2}$$ Attempt at solution : Let the given forces be ##\vec F_1=\vec A+\vec B## and ##\vec F_2=\vec A-\vec B## . Now, Resultant vector : ##\vec F_1 + \vec...