The idea was that you would transfer a dime from one mass to the other to get an increased acceleration from one trial to the next. It accelerates the system twice the weight on the dime faster as its removed from one and placed on the other, so the mass of the system is always constant. Now...
Homework Statement
I am given the equation (m1 – m2)g = (m1 + m2 + I/R2)a and the experiment is to validate this equation.
Homework Equations
The Attempt at a Solution
After following the lab guide, it tells you to plot the weight difference (m1– m2)g against acceleration and determine...
Right. Just so I am understanding that correctly.
In minutes my uncertainty is +/- 0.2, therefore on 20.0 minutes, it would remain as 20.0 +/- 0.2 min (both have the same amount of decimal places)
In hours the uncertainty would be +/- 0.003, where 20.0 min = 0.333 hr, would be 0.333 +/- 0.003...
Homework Statement
I am starting to confuse myself with the proper use of SF. I am to convert time from minutes to hours, keeping in mind proper SF
Homework Equations
conversion factor: 1 min = 1/60 hr
The Attempt at a Solution
The timing error is +/- 0.2 (1SF) = 0.003hr (1SF)
20.0...
If we know angular acceleration of the first half of the rotation (to horizontal), how could I use this value to figure out the angular velocity at the bottom? I'm assuming angular acceleration would be constant throughout??? I looked at some equations, but nothing that gave me the answer I had...
So I get:
ΣF = mg - FT = ma
FT = m(g - a)
= .3kg (9.8 - 0.12m/s^2)
= 2.9 N
Then for part c (mass of cylinder), I tried using α = a/r, τ = FTr, I = 1/2MR^2, and τR = Iα to solve for mass, but I'm still left with r from α = a/r
FTr x R = I α
FT R^2 = 1/2MR^2 α
FT = 1/2M a/r