Recent content by jdc15

Alright that seems to makes sense. But how is it immediately obvious that the wires labelled 4 and 8 connect to the OP AMP? Am I supposed to look this up on the datasheet? What about the connector labelled "7" on U1B?

Hmm, so it's not just me then. Pictures of the board are here (front and back): http://arduino.cc/en/uploads/Main/ArduinoUnoFront.jpg" http://arduino.cc/en/uploads/Main/ArduinoUnoBack.jpg" So the part labelled ICSP is for initial programming I see. I think there appears to be only one...

Alright, well, I've decided to start learning about how circuits work and as part of that I've looked into getting an Arduino, either by building one myself or buying one. I came across this tutorial here: http://www.instructables.com/id/DIY-Arduino-or-The-DIY-Duino/" I noticed that the design...

Yes, the field is 0 very far away. If you look at the vertex, try considering the effect of each wire segment to the magnetic field to that point. The two segments attached to the vertex won't contribute (if I'm not mistaken), but all of the other segments will.

Well, if you got the right answer, then it looks like you did the math right. But, there is still movement. Force doesn't directly cause there to be a velocity, it only causes acceleration. If there is no force, there is no chance in velocity, but there still can be movement.

So we have F=ma, and a=0, we get F = 0. This means the two forces must cancel out.

For the first part, I didn't look over it exactly but the method sounds alright. At a vertex, 0 doesn't sound quite right. If you sum up all of the contributions from the different wires you get something into the page. At a great distance, well you have an inverse square relation. What is...

That's right, there is no acceleration. According to Newton's second law, F=ma, if a = 0, then what happens to net force?

Nevermind I figured it out.

I think the problem is with this part: Fnetx=Fax-Fk ma=Facostheta-Fk 30.6a=400cos35.2-171.1 30.6a=326.9-171.1 30.6a=155.9 a=5.1m/s2 Where does 171.1N come from? Normally frictional force is \mu F_N.

Homework Statement a) Consider a driven mass-spring system with viscous friction using the notation of the lecture of Oct. 29, available on Vista. [The driving frequency is ω, the natural frequency is ω0, the friction force is -cv, the mass is m, the spring constant is k, the driving force is...

Well, when I say "conflict" I really mean seems to conflict haha. Here was the original problem: a) Consider a driven mass-spring system with viscous friction using the notation of the lecture of Oct. 29, available on Vista. [The driving frequency is ω, the natural frequency is ω0, the...

Alright thank you very much. This question relates to a physics problem I have which I might post later if I can't figure it out. Unfortunately this conflicts with what a TA told me. Oh well I'll figure it out. Thanks again.

By the intermediate value theorem, if we can find a value of x for which f(x)<119 and a value of x for which f(x)>119, and f(x) is continuous, then somewhere along that interval f(x)=119. That's how the theorem works. To prove continuity, there are a bunch of rules. f(x)/g(x) for example is...

Maybe our friend L'Hopital can help: http://en.wikipedia.org/wiki/L%27H%C3%B4pital%27s_rule"