Power of a driven oscillating spring

Click For Summary
SUMMARY

The discussion focuses on the analysis of a driven mass-spring system with viscous friction, specifically addressing the formulas for energy loss due to friction and work done by the driving force. Key variables include the driving frequency (ω), natural frequency (ω0), friction force (-cv), mass (m), spring constant (k), and driving force (kD sin(ωt)). The participant successfully derived the power equation as p = -cA²ω²cos²(ωt + φ) but sought clarification on the integration process for work, which involves time-dependent variables.

PREREQUISITES
  • Understanding of harmonic motion and oscillations
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of energy concepts in mechanical systems
  • Basic principles of friction and damping in physics
NEXT STEPS
  • Study the derivation of energy loss formulas in driven oscillatory systems
  • Learn about the relationship between work and energy in mechanical systems
  • Explore the implications of damping on oscillatory motion
  • Investigate the use of phase angles in oscillatory systems
USEFUL FOR

Physics students, mechanical engineers, and anyone studying oscillatory systems and energy dynamics in mechanical contexts.

jdc15
Messages
40
Reaction score
0

Homework Statement



a) Consider a driven mass-spring system with viscous friction using the notation of the lecture of Oct. 29, available on Vista. [The driving frequency is ω, the natural frequency is ω0, the friction force is -cv, the mass is m, the spring constant is k, the driving force is kD sin (ω t). Note that the phase Φ is negative, between 0 and π .] Write a formula for the rate of energy loss due to the friction force, once the steady state has been reached, as a function of time, t.

b) Write a formula for the rate at which the driving force is doing work on the mass-spring system, once the steady state has been reached, as a function of time, t.

c) Find the total energy loss due to friction over one period of the oscillations and also the total work done by the driving force over one period. Check whether or not they are equal. To do this problem you need to use the fact that the integral of a sine or cosine function over one period is zero. This integral is simply the average value over one period divided by the period. This is clearly zero if you think about what a cosine or sine function looks like.

Homework Equations



We have the equation for work: W=\int{F}\cdot dr
Power: dW/dt
Position: r=Asin(\omega t + \phi )
Velocity: v=dr/dt
Frictional force: F_f=-cv
Driving force: F_D=kDsin(\omega t)
Amplitude: A is a complex formula involving \omega, \omega 0, k, m, c (will post later if needed)

The Attempt at a Solution



For a, I went r=Asin(wt+phi) so dr=Awcos(wt+phi)dt and v=Awcos(wt+phi). Thus work is \int{-cvA\omega cos(\omega t + \phi )} dt, so power is p=-cA^2\omega^2cos^2(\omega t + phi). Now this answer makes sense to me, I know I'm missing a phi term that I need to solve for, but it seems to match the simulations we've been shown. However, my TA told me I should separate the integral \int{F}dr=F\int{}dr=Fr but this doesn't make sense to me because r and F both depend on time. Does anyone have an explanation?

Thanks in advance.

PS. This is a continuation of another post that originally was just a calc question: https://www.physicsforums.com/showthread.php?p=2967731&posted=1#post2967731"
 
Last edited by a moderator:
Physics news on Phys.org
Nevermind I figured it out.
 

Similar threads

Replies
9
Views
2K
Replies
17
Views
3K
Replies
39
Views
5K
Replies
1
Views
1K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 70 ·
3
Replies
70
Views
6K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K