Recent content by jkristia

>>In the future, when you post a new problem, please start a new thread ok, I will remember that >>That's correct, but you could go further and Good point. But in this case since I don't start out with a y = ... , but rather yx = ..., then I'm not sure if it would be expected. If I were...

Instead of starting a new thread, I will post the second problem here. I think I have done this one correct, but as with the first problem, I really have no idea if it is correct or not

wow, thank you very much for the quick reply

I'm preparing for a test next week and am working on some practice problems we got, but we did not get the answers. There are 2 problems where I'm not sure if I have done it correct or not and would like to have it checked. This is the first problem. I think I have followed the chain, product...

>>Personally, I'd just expand the binomial then differentiate twice That certainly makes it much easier. I guess I didnt think of that since I was doing problems related to the chain rule. Thank you for your suggestion.

The problem and my attempt at a solution is shown in the attached image. The problem is that I end up with one extra x in the denominator. So the question is: Is my expression for y'' correct and I just made a mistake somewhere (I have checked it several times), or am I missing something in the...

Thank you. I think replacing 1/2 with sin(pi/6) is what I was missing. I know the limit of sin(x)/x = 1.

Thank you for your suggestion, but even with substitution I keep going in circles. I will continue looking at this tomorow. As for not using L'Hopital, I'm doing self study at the moment, working through problems in the book, and L'Hopital is not covered until another 7 chapters, so I figured...

limit problem with sin(x) / ... Homework Statement I'm stuck trying to algebraically find the limit of this expression shown below. If I use L'Hospital I get the answer (√3) / 2 which is the correct answer, but it seems like no matter what I try I end up with 0/0. Any hints of how to...

>>Substitute u=sinθ. Ah yes of course. ∫(1 - u2) du u - u3/3 + C Thank you very much.

I know the answer is (sinθ - \frac{sin^3}{3}) + C and I can see how to differentiate this cosθ - \frac{3}{3}sin^2θcosθ = (1- sin^2θ)cosθ But I can't see what I'm doing wrong when trying to go the opposite direction

θHomework Statement I'm trying to do an integration by substitution, but I'm completely stuck at the moment ∫(1-sin2θ)cosθ dθ Homework Equations ∫u dv = uv - ∫v du The Attempt at a Solution u = 1 - sin2θ dv = cosθ dθ du = -2sinθcosθ or -sin(2θ) v = sin I found du as...

Thank you very much for the quick reply. I'm trying to do calculus as a selfstudy, and the L'Hospital is not mentioned until another 320 pages.

I'm still trying to figure out how to do limits of trig functions and I would like to know if this is the correct approach. I know the answer is correct, but not sure if that is just a coincidence. Homework Statement lim (x -> 0) of (sin 2x) / (sin3x). Homework Equations The Attempt at a...