Is my approach to finding the limit of trig functions correct?

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SUMMARY

The discussion centers on evaluating the limit of the trigonometric function lim (x -> 0) of (sin 2x) / (sin 3x). The user successfully applies the technique of rewriting the limit into the form (sin x) / x, multiplying by appropriate factors to simplify the expression. The final result is confirmed as 2/3, demonstrating the correctness of the approach. An alternative method using L'Hospital's Rule is mentioned but deemed less elegant by the user.

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I'm still trying to figure out how to do limits of trig functions and I would like to know if this is the correct approach. I know the answer is correct, but not sure if that is just a coincidence.

Homework Statement



lim (x -> 0) of (sin 2x) / (sin3x).

Homework Equations


The Attempt at a Solution



First I try to get the equation into the form (sin x) / x or x / (sin x)
so I multiply by

(x/x)(3/3)(2/2)

this gives me

(1/3)(3x/sin3x)(2/1)(sin2x/2x)

so I get
(1/3)(1)(2/1)(1) = 2/3

Is that the correct approach?
 
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Yes, it is :smile:

Edit : Another way to solve this would be the use of L'Hospital principle, but this method is more elegant, in my opinion.
 
Thank you very much for the quick reply.

I'm trying to do calculus as a selfstudy, and the L'Hospital is not mentioned until another 320 pages.
 

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