Recent content by Jonski

Sorry the reason why I got what i did for H(w), was because I forget to put in an absolute around the t. I've changed in now

So then using that you would get that Y(w) = 4π/(1+w2) * δ(w-2), but then how would you get that back into the time domain?

Homework Statement An LTI system has an impulse response h(t) = e-|t| and input of x(t) = ejΩt Homework Equations Find y(t) the system output using convolution Find the dominant frequency and maximum value of y(t) Ω = 2rad/s The Attempt at a Solution I have tried using the Fourier transform...

Homework Statement Gear 2 in the figure below is driven at a speed of 80 rpm in the CCW direction viewed from the right end. Gear 4 meshes with a fixed ring gear (gear 7) and with gear 5. Find the angular velocity of gear 5. N2= 16 T, N3= 32 T, N4= 30 T, N5= 22 T and N7= 77 T. Homework...

Wouldn't the velocity perpendicular to BC be equal to: Vb = Vb' + Vb/b' Vb = 17(0.0335) + 0.8 Vb = 1.37 m/s

Does it have something to do with the fact that since the angular velocity of bar AB is constant the tangential acceleration of bar AB is 0.

Homework Statement In the mechanism shown below, the angular velocity of link 2 is 17 rad/s CW, constant. Find the angular velocity (magnitude and direction) of link 3. The distance between A and C is 109 mm, the length of link 3 is 125 mm, and θ= 111°. Note: B is a pin-slider In the...

Oh, thanks. I understand now

Homework Statement Homework Equations [/B] Va = Va/c + Vc Va = 0.2 + Vc Vb = Vd The Attempt at a Solution I began by finding the instant centre of rotations of AB and CD. Both of these form a right angle triangle and the length of A -> ICab = 200mm and C -> ICcd = 300mm Va/0.2 * 0.15 = Vb...

So could I say that the instantaneous centre of OA is at C: 7.2/0.042 = 171.429 rad/s = Woa Va = 171.429*0.0289 = 4.954 m/s Then we can construct a right angle trigangle of Va, Vb and Va/b with angle 73 degrees. Then for Vb it would be Va/sin(73) = 5.18m/s => -5.18m/s (right is positive)...

Would A be moving straight down as that would be perpendicular to OA?

Homework Statement A wheel of radius 42 mm is rolling without slipping and its centre O has a velocity 7.2 m/s in the direction shown. The slider B is driven by the link AB and A is connected to the wheel. If AC= 28.9 mm, AB= 73.9 mm and angle ACB= 73°, what is the velocity of the slider B...

So would it be more like: (-29.18*0.052)/(1.57x10^-8 * 83x10^9) + (1100.82*0.092)/(J * 83x10^9) + (-249.18*0.111)/(J * 83x10^9) + (-779.18*0.138)/(J* 83x10^9)

But the -29.18 is the internal torque between them, so doesn't that account for torque both sides of the gear

Homework Statement What is the angle of twist at gear A relative to the motor? (Round to the closest 6th decimal) Homework Equations I know to find the angle its θ = ∑ (TL/JG) but it can also be θ = Lτ/Gr The Attempt at a Solution So i used both these equations, and I got...