What is the solution for relative velocity of sliders?

Click For Summary
SUMMARY

The discussion centers on solving the relative velocity of sliders using the instant center of rotation method. The participant calculated velocities Va, Vb, Vc, and Vd based on given lengths and angles, ultimately arriving at an answer of 0.0536 m/s. The confusion arose from the sign convention used for the velocities, specifically treating Va as positive to the right and Vc as positive to the left. Clarification was provided that Va should be expressed as 0.2 - Vc to resolve the issue.

PREREQUISITES
  • Understanding of relative velocity concepts
  • Familiarity with instant center of rotation methodology
  • Basic knowledge of kinematics and vector addition
  • Ability to solve right angle triangles in physics problems
NEXT STEPS
  • Study the principles of relative velocity in mechanics
  • Learn about the instant center of rotation technique in detail
  • Practice solving kinematic problems involving multiple sliders
  • Explore vector addition and its applications in physics
USEFUL FOR

Students in physics or engineering courses, particularly those focusing on mechanics and kinematics, as well as educators looking for examples of relative velocity problems.

Jonski
Messages
42
Reaction score
0

Homework Statement


Screen Shot 2016-10-01 at 6.08.41 PM.png


Homework Equations

[/B]
Va = Va/c + Vc
Va = 0.2 + Vc
Vb = Vd

The Attempt at a Solution


I began by finding the instant centre of rotations of AB and CD. Both of these form a right angle triangle and the length of A -> ICab = 200mm and C -> ICcd = 300mm
Va/0.2 * 0.15 = Vb
Vc/0.3 * 0.125 = Vd
Va/0.2 * 0.15 = Vc/0.3 * 0.125
0.75*(0.2+Vc)=0.417(Vc)
Vc = -0.45
Vd = -0.1875m/s = Vb

The answer is 0.0536m/s, but I am not sure why taking the instant centre does not work. Did I mess anything up. Thanks in advance
 
Physics news on Phys.org
Jonski said:

The Attempt at a Solution


I began by finding the instant centre of rotations of AB and CD. Both of these form a right angle triangle and the length of A -> ICab = 200mm and C -> ICcd = 300mm
Va/0.2 * 0.15 = Vb
Vc/0.3 * 0.125 = Vd
Va/0.2 * 0.15 = Vc/0.3 * 0.125
0.75*(0.2+Vc)=0.417(Vc) ##~~~~##←
Vc = -0.45
Vd = -0.1875m/s = Vb

The answer is 0.0536m/s, but I am not sure why taking the instant centre does not work. Did I mess anything up. Thanks in advance
I believe that your problem lies at the line indicated above. It appears to me that you've taken velocity Va to be positive to the right and Vc to be positive to the left. Then your Va + Vc = 0.2 and so Va = 0.2 - Vc.
 
gneill said:
I believe that your problem lies at the line indicated above. It appears to me that you've taken velocity Va to be positive to the right and Vc to be positive to the left. Then your Va + Vc = 0.2 and so Va = 0.2 - Vc.
Oh, thanks. I understand now
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 27 ·
Replies
27
Views
5K
Replies
1
Views
2K
Replies
2
Views
9K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
11K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K