Recent content by Jrlinton

Correction: The given solution was y=3e^(2t)+5e(-2t). I understand how he got this by using partial fractions, I would just like to know if the two functions are equivalent or if there was a mistake.

Homework Statement Y=(8s-4)/(s²-4) Homework EquationsThe Attempt at a Solution I rearranged the right side as: 8*(s/(s²-2²))-2*(2/(s²-2²)) Using the Laplace transform chart given in the class I was able to identify these as the transforms of hyperbolic sine and hyperbolic cosine making the...

Yes, I am having trouble coming up with the integral.

Homework Statement Homework Equations C=Δq/VThe Attempt at a Solution So part a: The capacitance of 3 should be the difference in charge of b and a divided by the voltage of the circuit? C3=(14μC-6μC)/12V =6.67*10-7 F This was wrong...

So if U am understanding this correctly then it is the added sine values of the two angles created when drawing the vector for the field?

Homework Statement So this was a problem worked in class by the professor in class. Find the net electric field at the origin due to the arcs Homework Equations L=2πr/4 λ=q/L E=kQ/r2 The Attempt at a Solution So the professor gave the answer using the fromula...

Nevermind, forgot to square the distance.

Homework Statement Homework Equations E=kq/r2 The Attempt at a Solution So i decided to do decouple the x and y values to make it simpler For Ex It became apparent through the geometry and charges that there would be no net field in the x direction For Ey: k/r2*...

Thanks haruspex. I missed that negative sign.

I understand that the function cannot determine the quadrant of the angle and just assumes that it is in the first two quadrants. I also understand that this particular would be in the third quadrant. I suppose that what I am having trouble with is if it is asking for θ being the blue, yellow...

Homework Statement The electric potential at points in an xy plane is given by V = (1.5 V/m2)x2 -(2.9 V/m2)y2. What are (a) the magnitude of the electric field at the point (3.9 m, 2.9 m) and (b) the angle that the field there makes with the positive x direction. Homework EquationsThe Attempt...

I appreciate it, thank you.

I should have read your instructions more carefully... ε0

that didn't seem to work.. let's try 0ε

ε0