Calculating Capacitance in Closed Loop Circuits

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SUMMARY

The discussion focuses on calculating capacitance in closed loop circuits, specifically addressing the formula C=Δq/V. A participant incorrectly calculated the capacitance of capacitor C3 by using the total voltage of 12V instead of the voltage across C3. The correct approach involves applying voltage divider equations to determine the voltage across individual capacitors. The accurate calculation for C3 requires using the difference in charge (Δq) divided by the specific voltage across C3.

PREREQUISITES
  • Understanding of capacitance and the formula C=Δq/V
  • Familiarity with voltage divider equations in capacitive circuits
  • Basic knowledge of charge (μC) and voltage (V) units
  • Ability to analyze closed loop circuits
NEXT STEPS
  • Study voltage divider equations for capacitive circuits
  • Learn how to calculate voltage across individual capacitors in a closed loop
  • Explore practical examples of capacitance calculations in circuit analysis
  • Review the principles of charge distribution in capacitors
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone involved in analyzing closed loop circuits and capacitance calculations.

Jrlinton
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Homework Statement


upload_2017-2-23_13-10-42.png


Homework Equations


C=Δq/V

The Attempt at a Solution


So part a:
The capacitance of 3 should be the difference in charge of b and a divided by the voltage of the circuit?
C3=(14μC-6μC)/12V
=6.67*10-7 F
This was wrong...
 
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Jrlinton said:
The capacitance of 3 should be the difference in charge of b and a divided by the voltage of the circuit?
No. You need to divide it by the voltage across C3, which is not same as total voltage in the circuit. Use voltage divider equations for capacitive circuits.
 

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