Calculating Capacitance in Closed Loop Circuits

[Jrlinton]

Homework Statement

Homework Equations

C=Δq/V

The Attempt at a Solution

So part a:
The capacitance of 3 should be the difference in charge of b and a divided by the voltage of the circuit?
C₃=(14μC-6μC)/12V
=6.67*10^-7 F
This was wrong...

 

[cnh1995]

The capacitance of 3 should be the difference in charge of b and a divided by the voltage of the circuit?

No. You need to divide it by the voltage across C3, which is not same as total voltage in the circuit. Use voltage divider equations for capacitive circuits.