Recent content by jzwiep

Alright, thanks for the help.

Okay it looks like I did the quadratic wrong, (27.44m + 117.895m)/144 k=1.00927m Which gives f=0.15989Hz But that's not a factor of 10 off. I double checked my algebra for: 1/2k^{2}A^{2} - kmgh-1/2m^{2}g^{2} =0 And it looks right. Do you know if I'm getting my error from here...

Ah, that was silly of me So changing that gives me: 72k^{2} - 27.44mk - 48m^{2} Which works out to: k=1.02899m Giving me a: f=http://www.wolframalpha.com/input/?i=sqrt%281.02899%29%2F%282pi%29" Is that correct?

dL=mg/k 1/2k(A+mg/k)^{2}=mg(A+mg/k+h) 1/2kA^{2} + 1/2m^{2}g^{2}/k = mg(A+h) + m^{2}g^{2}/k 1/2k^{2}A^{2}- kmg(A+h)-1/2m^{2}g^{2}=0

If you wouldn't mind doing so that'd be great. Thanks.

Homework Statement You want to do an experiment using 47Ca (half-life=4.53 days). You will need 3.25 μg of the nuclide. What mass of CaCO3 (100% enriched in 47Ca) must you order if it will take 50 hours to be delivered to you from the nuclear facility where it is prepared? Homework...

Is this now the correct formula? I only have a few attempts left so I didn't want to check if the answer was right.

Etotal=Us=Up 1/2kA^2=mg(A+dL+h) I rearrange with equilibrium forces equation to get: 6k^2-145mk-96m^2=0 Then using the quadratic equation to yield: (145m +/- 220.62m)/144 So k=2.539m Then I substituted in for k in f=(1/2pi)sqrt(k/m) f=(1/2pi)sqrt(2.539) =3.9883Hz =4.0Hz Which wasn't...

Alright, I tried using conservation of energy. U=mg(A+dL+h) Where A is the amplitude, dL is the spring compression to equilibrium, and h is the height the height the mass was dropped above the spring. Along with: Fg=Fs mg=k*dL and f=(1/2pi)sqrt(k/m)Am I at least on the right track? I...

Okay, so I found the formula relating k to f: f=(1/2pi)sqrt(k/m) I haven't been able to find anything that would relate k to A without any additional variables (like the vmax formula in terms of k, m, and A). Whatever it is has to cancel out the mass in the f formula, but is there more...

Homework Statement A spring is standing upright on a table with its bottom end fastened to the table. A block is dropped from a height 2.8 cm above the top of the spring. The block sticks to the top end of the spring and then oscillates with an amplitude of 12 cm. What is the oscillation...

The correct answer was: F=Mg/3 Which is just 3T=mg rearranged and with T=F Am I really that far off? Could you be a little more specific please? I'm not really sure what you're saying. Which pulley did I create an imaginary force at?

Homework Statement A window washer of mass M is sitting on a platform suspended by a system of cables and pulleys as shown . He is pulling on the cable with a force of magnitude F. The cables and pulleys are ideal (massless and frictionless), and the platform has negligible mass...

Thanks. I drew the triangle backwards.

Homework Statement MP 11.44 Sam, whose mass is 75kg, straps on his skis and starts down a 50-m-high, 20degree frictionless slope. A strong headwind exerts a horizontal force of 200N on him as he skies. Find Sam's speed at the bottom (a) using work and evergy (b) Using Newton's laws...