Mass of Nuclide Remaining After a Fraction of a Half-Life

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SUMMARY

The discussion revolves around calculating the mass of calcium carbonate (CaCO3) required to obtain 3.25 μg of the nuclide 47Ca, which has a half-life of 4.53 days. The user correctly converts the half-life into hours and determines that 50 hours corresponds to approximately 0.4599 half-lives. However, the user fails to account for the total mass needed before decay, leading to an incorrect conclusion. The correct calculation shows that 4.47 μg of 47Ca must be ordered to ensure 3.25 μg remains after 50 hours.

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jzwiep
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Homework Statement



You want to do an experiment using 47Ca (half-life=4.53 days). You will need 3.25 μg of the nuclide. What mass of CaCO3 (100% enriched in 47Ca) must you order if it will take 50 hours to be delivered to you from the nuclear facility where it is prepared?

Homework Equations





The Attempt at a Solution



4.53 days x 24 hrs/day = 108.72 hrs

50/108.72 = 0.4599 half-lives

(1/2)^0.4599 = 0.727

3.25 μg / 0.727 = 4.47 μg

Am I doing something wrong? All the ways I've seen to do this type of problem lead me to the same answer, but it says it's incorrect.
 
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jzwiep said:

Homework Statement



You want to do an experiment using 47Ca (half-life=4.53 days). You will need 3.25 μg of the nuclide. What mass of CaCO3 (100% enriched in 47Ca) must you order if it will take 50 hours to be delivered to you from the nuclear facility where it is prepared?

...


Am I doing something wrong?
All the ways I've seen to do this type of problem lead me to the same answer, but it says it's incorrect.

I don't think so but you haven't finished, read the question carefully!
 

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