Recent content by KevMilan

When you say with respect to air, basically whatever the wind speed is, it'll always be moving at 200km/h in the wind's perspective, right? So the word 'still air' in the question is crucial to finding this solution?

A lot of sites have been saying this but I still don't get why the hypotenuse is 200, can you kindly explain this in detail?

I used pythagoras theorem, I assumed 200km/h as facing north and 85km/h facing east, and the hypotenuse would be 217km/h.

Summary: I've posted this in a few forums but still confused on this problem. If the plane is moving at 200km/h and the wind pushes the plane with a velocity of 85km/h, then the resultant velocity would be 217km/h, and using sine inverse, 217.sin(theta=85, I got 23°, which is B, but the answer...

I see. Thanks a lot man [emoji106]

One more thing, why is it the workdone BY the sample (not ON)? (Is it because we're not putting any force/tension on the sample when unloading?) Any simple explanation would be very helpful!

For the area under the loading curve, shouldn't it be the workdone ON the sample? Because we are the one putting force/stress on it? Could you clarify? Thankyou.

What about the area under the loading curve? Is it the workdone on the sample or by the sample?

The answer says B, it does makes sense, but why D is regarded as incorrect. If the Elastic Potential energy when loading is the area under the loading curve, so why not with the unloading?

Yes Yes, it affects both of them, I just don't understand how the resistor from the secondary creates a resistance like effect in the primary (25 Ohms), the fact that the primary circuit doesn't have any resistor connected to it.

Thanks for the reply, just like what I thought (they are magnetically linked), but I am just having a hard time on how the 5 Ohms Resistor causes the Primary to act as if there was a 25 Ohms resistor, I'm guessing it has relation to Lenz's Law (Back EMF) from the secondary winding producing an...

Let's assume a 2:1 transformer which has a 100V Source connected on the primary circuit and has no/negligible resistance, on the secondary circuit a 5 Ohms resistor is connected. Using the 'Impedance Transfer/Reflection' method, the primary circuit would act as if there was a 25 Ohms resistor...