How a Secondary Resistor affects the Transformer Primary Side?

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Discussion Overview

The discussion centers on the effect of a secondary resistor on the primary side of a transformer, specifically examining how the secondary load influences the apparent resistance seen by the primary circuit. Participants explore concepts related to impedance reflection, magnetic coupling, and energy conservation within the context of a 2:1 transformer setup.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant describes a scenario with a 2:1 transformer and a 5 Ohm resistor on the secondary side, suggesting that the primary circuit behaves as if it has a 25 Ohm resistor due to impedance reflection.
  • Another participant asserts that the circuits are not separate, as they are mutually coupled through magnetic fields, which influences both primary and secondary currents.
  • There is a suggestion that Lenz's Law may explain the opposing current in the primary due to the secondary resistor, though further clarification is sought.
  • One participant questions the intuition behind how changing the secondary resistance affects both primary and secondary currents, indicating a lack of clarity on the relationship.
  • A later reply corrects the initial impedance reflection value to 20 Ohms instead of 25 Ohms, emphasizing the importance of energy conservation in understanding the apparent resistance seen by the primary source.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the exact nature of the resistance-like effect created by the secondary resistor on the primary side. While there is agreement on the concept of magnetic coupling, the specific values and implications of impedance reflection remain contested.

Contextual Notes

There are unresolved questions regarding the intuitive understanding of how secondary resistance influences primary circuit behavior, as well as the mathematical steps leading to the corrected impedance value.

KevMilan
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Let's assume a 2:1 transformer which has a 100V Source connected on the primary circuit and has no/negligible resistance, on the secondary circuit a 5 Ohms resistor is connected. Using the 'Impedance Transfer/Reflection' method, the primary circuit would act as if there was a 25 Ohms resistor connected to it, which means a current of 4 Amps would be flowing in the Primary.

My question is how the 5 Ohms resistor from the secondary side 'actually' affects/creates a 'resistance-like effect on the primary side? Aren't they separate circuits? Or does it has to do with the magnetic field that links one another?

A simple concise explanation would be very helpful!
 

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KevMilan said:
Aren't they separate circuits? Or does it has to do with the magnetic field that links one another?

No they are not really separate. They are mutually coupled by the magnetic fields as you guessed.
 
anorlunda said:
No they are not really separate. They are mutually coupled by the magnetic fields as you guessed.
Thanks for the reply, just like what I thought (they are magnetically linked), but I am just having a hard time on how the 5 Ohms Resistor causes the Primary to act as if there was a 25 Ohms resistor, I'm guessing it has relation to Lenz's Law (Back EMF) from the secondary winding producing an opposing current in the Primary, but there still isn't any clarification and further explanation regarding the question above.
 
The mutual coupling comes via the time changing currents in the coils. So if the secondary resistance was infinite, then no secondary current and there is no coupling.

So, i isn't that intuitive that changing the secondary resistance changes both secondary and primary currents?
 
anorlunda said:
The mutual coupling comes via the time changing currents in the coils. So if the secondary resistance was infinite, then no secondary current and there is no coupling.

So, i isn't that intuitive that changing the secondary resistance changes both secondary and primary currents?
Yes
anorlunda said:
The mutual coupling comes via the time changing currents in the coils. So if the secondary resistance was infinite, then no secondary current and there is no coupling.

So, i isn't that intuitive that changing the secondary resistance changes both secondary and primary currents?
Yes, it affects both of them, I just don't understand how the resistor from the secondary creates a resistance like effect in the primary (25 Ohms), the fact that the primary circuit doesn't have any resistor connected to it.
 
KevMilan said:
Yes, it affects both of them, I just don't understand how the resistor from the secondary creates a resistance like effect in the primary (25 Ohms), the fact that the primary circuit doesn't have any resistor connected to it.

You sound confused. If it affects both of them, how would you describe the effect? Would the effect not look analogous to a resistance in the primary circuit?
 
KevMilan said:
View attachment 239280

Let's assume a 2:1 transformer which has a 100V Source connected on the primary circuit and has no/negligible resistance, on the secondary circuit a 5 Ohms resistor is connected. Using the 'Impedance Transfer/Reflection' method, the primary circuit would act as if there was a 25 Ohms resistor connected to it, which means a current of 4 Amps would be flowing in the Primary.

My question is how the 5 Ohms resistor from the secondary side 'actually' affects/creates a 'resistance-like effect on the primary side? Aren't they separate circuits? Or does it has to do with the magnetic field that links one another?
The secondary resistance reflected into the primary is 20 ohms, not 25 ohms.

The transformer, containing no resistance in either primary or secondary windings, itself dissipates no power. So in order to conserve energy, the power supplied to the load must equal the power furnished by the primary source.

So V22/R2 = V12/R1. So the primary source MUST "see" R1 = (V1/V2)2R2 = 22R2 = 20Ω.

Whethere or not you understand principles of magnetic coupling, energy conservation forces you to realize that the primary source "sees" 20Ω.
 

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