A. Invertible. Let's call this transformation T which as a transformation matrix A. So since it is invertible there exists an A^-1 such that: T(<x,y,z>)= <x1,y1,z1> where A<x,y,z> = <x1,y1,z1> so that A^-1 <x1,y1,z1> = <x,y,z> for any given plane
and something like that for the other ones or...