What is the polar form of -2^i?

[KyleS4562]

Homework Statement

Convert -2^i to polar and rectangular form

Homework Equations

mag(a+ib)=sqrt(a^2+b^2)

exp(i*angle)=cos(angle)+i*sin(angle)

The Attempt at a Solution

im not sure how to get the polar (or rectangular form) of -2^i.
i know the answer is exp(-2.448rad)... i just don't know the property that allows me to get there or to the rectangular form

 

[eumyang]

Use the properties of logarithms to convert the 2 into a power of e, ie.
$$2 = e^{something}$$
(And yes, I know that 2 is negative. Let's not worry about it right now.)

 

[KyleS4562]

i see wat to do now... thank you... it would be 2=exp(ln2) which means 2^i=exp(ln(2^i))=exp(i*ln(2)) which is polar form... totally forgot the properties of log

 

[HallsofIvy]

By $-2^i$ do you mean $-(2^i)$ or $(-2)^i$. They are different numbers.