Recent content by lpcampbe

Thanks, Bright Wang. That helped a lot. The Fa you used in that equation, is that the parallel force?

That's what I thought, but I have no idea how to do this problem. I used the Fx equation I listed above but it doesn't include the friction coefficient.

Two masses are being pulled up a 30 degree incline by a force F parallel to the incline. The velocity is constant and up the incline. The force is applied to a 200 kg mass and a string connects the 200 kg mass to a 150 kg mass. The coefficient of kinetic friction is 0.2. The force F = ? So I...

A car can negotiate an unbanked curve safely at a certain maximum speed when the coefficient of static friction between the tires and the ground is 0.84. at what angle should the same curve be banked for the car to negotiate the curve safely at the same maximum speed without relying on friction...

it's okay hage567, i had lecture today and my professor just went over the material on the homework that was due yesterday, so. this should be an interesting semester... looks like I'm going to go to the help room a lot.

Homework Statement Puck A has a mass of 0.236 kg and is moving along the x-axis with a velocity of 5.56 m/s. It makes a collision with puck B, which has a mass of 0.472 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown...

Homework Statement A person is standing on a sheet of ice so slippery that friction may be ignored. This individual fires a gun parallel to the ground. When a standard cartridge is used , a 17-g bullet is shot forward with a speed of 280 m/s, and the person recoils with a speed of vc. When a...

ooooh. haha, it's always something like that that gets me. last time i forgot to change my calculator into degrees... thanks for the help. :) note to self: always read the problem a couple times!

kJoule? The units are J, not kJ. One of the things the website says is to enter at least 3 sig figs. "Unless otherwise noted, treat all numerical values given in CHIP problems as if they were exact. Use the physical and other constants as provided in the tables linked from CHIP or in your texts...

So, if I'm understanding you correctly, Mattowander, I should be able to say the work done by air resistance is -28.84 J. And I think Almanzo is saying pretty much the same thing. There's only one problem. -28.84 J isn't right. (online homework and it gave me a big fat red NO when I entered that...

Oooooh. Now I get it. So -5.5 km * 2.2 N = -12.1 J. So I have -16.74 J and -12.1 J. Do I sum the vectors? I added the work done together and I don't think that's right. But they're not vectors, because they don't have direction. Work is a scalar, so how do I combine the two?

Okay, so the bicyclist only travels 0.7 km total. But where does the air resistance come into play then?

A bicyclist rides 6.2 km due east, while the resistive force from the air has a magnitude of 2.7 N and points due west. The rider then turns around and rides 5.5 km due west. The resistive force from the air on the return trip has a magnitude of 2.2 N and point due east. Find the work done by...

Thanks, LowlyPion! I also tried to find a using Vf^2 = Vi^2 + 2ax and i got this same answer, but the equation you gave me made my life so much easier. :) Thanks again!

A top fuel drag racer with a mass of 600.0 kg completes a quarter-mile (402 m) drag race in a time of 4.4 s starting from rest. The car's final speed is 115 m/s. What is the engine's average power output? Neglect friction and air resistance. I know: Power = Work/ change in time W = Force *...