Answer: Calculate Average Power Output for 600 kg Top Fuel Drag Racer

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SUMMARY

The average power output of a top fuel drag racer with a mass of 600 kg completing a quarter-mile in 4.4 seconds and reaching a final speed of 115 m/s is calculated to be 1432.747 kW. The calculations involve determining acceleration using the formula Vf = Vi + at, resulting in an acceleration of 26.1364 m/s². The force is then calculated as F = mass * acceleration, yielding 15681.8182 N. Work is computed as W = Force * distance, leading to a total work of 6304090.909 J, which is divided by time to find power.

PREREQUISITES
  • Understanding of basic physics concepts such as force, work, and power
  • Familiarity with kinematic equations, specifically Vf = Vi + at
  • Knowledge of energy concepts, particularly kinetic energy calculations
  • Ability to convert units, specifically from watts to kilowatts
NEXT STEPS
  • Study the concept of kinetic energy and its relation to work done
  • Learn about the implications of neglecting friction and air resistance in physics problems
  • Explore advanced kinematic equations for different scenarios
  • Investigate the performance characteristics of top fuel drag racers
USEFUL FOR

Physics students, automotive engineers, and motorsport enthusiasts interested in understanding the dynamics of drag racing and power output calculations.

lpcampbe
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A top fuel drag racer with a mass of 600.0 kg completes a quarter-mile (402 m) drag race in a time of 4.4 s starting from rest. The car's final speed is 115 m/s. What is the engine's average power output? Neglect friction and air resistance.

I know:
Power = Work/ change in time
W = Force * change in distance
F = mass * acceleration
Vf = Vi + at

so i solve for a
115 m/s = 0 m/s + a(4.4 s)
a = 26.1364 m/s^2

then i solve for F
F = 600 kg * 26.1364 m/s^2
F = 15681.8182 N

then i solve for W
W =15681.8182 N * 402 m
W = 6304090.909 J

then i solve for P
P = 6304090.909 J / 4.4 s
P = 1432747.934 W

I'm supposed to answer in kW
P = 1432.747 kW

I don't understand why this answer is wrong!
 
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lpcampbe said:
A top fuel drag racer with a mass of 600.0 kg completes a quarter-mile (402 m) drag race in a time of 4.4 s starting from rest. The car's final speed is 115 m/s. What is the engine's average power output? Neglect friction and air resistance.

I know:
Power = Work/ change in time
W = Force * change in distance
F = mass * acceleration
Vf = Vi + at

so i solve for a
115 m/s = 0 m/s + a(4.4 s)
a = 26.1364 m/s^2

then i solve for F
F = 600 kg * 26.1364 m/s^2
F = 15681.8182 N

then i solve for W
W =15681.8182 N * 402 m
W = 6304090.909 J

then i solve for P
P = 6304090.909 J / 4.4 s
P = 1432747.934 W

I'm supposed to answer in kW
P = 1432.747 kW

I don't understand why this answer is wrong!

Perhaps you want to consider that

Work = \Delta KineticEnergy = \frac{m*v^2}{2} - 0
 
Thanks, LowlyPion!

I also tried to find a using Vf^2 = Vi^2 + 2ax and i got this same answer, but the equation you gave me made my life so much easier. :)

Thanks again!
 

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