Recent content by mite

How to find the resolution of a Michelson interferometer ?

Right thank you :smile:

In the question all the options are expressed in terms of " h " rather then " \hbar " so i used \hbar=h/(2\Pi) hence i got the last step

\Psi=\sqrt{}(2/L) Sin(\Pix/L) <x>=\int(2/L) (Sin(\Pix/L)^2 x dx {in the limit 0 to L} <x>=L/2 <x^2>=\int(2/L) (Sin(\Pix/L))^2 x^2 dx {in the limit 0 to L} <x^2>=(L^2 / 3) - ( L^2 / (2 \Pi^2) <p>=\int(2/L) Sin(\Pix/L) (-i \hbar d/dx) Sin(\Pix/L) dx {in the limit 0 to L} <p>=0...

For the ground state of a particle moving freely in a one-dimensional box 0\leqx\leqL with rigid reflecting end-points, the uncertainty product (del x)(del p) is 1 h/2 2 sqrt{2}h 3 >h/2 4 h/sqrt{3} I used (del x)^2 =<x^2>-<x>^2 and (del p)^2 =<p^2>-<p>^2 Using the wavefunction of...

Yes I got it thank you

i tried doing that one time when there is a sine function other terms have x terms so at x=0 it is zero another time when there is cos function there is one term such as exp(-(x^2/2)) which cancels it so at x=0 it is zero

It is e^(-(x^2)/2) .when both are considered second derivative is zero

f(x)=Cos(x)-e^(-x^2/2) Value of f(x) at x=0.01 I tried linearising at x=0 but higher derivatives are zero at x=0 .Please help me proceed

Is time travel possible quantum world?

How to plot this vector field on a graph \stackrel{}{\rightarrow} V=(xi+yj+zk)/\sqrt{}(x^2+y^2+z^2)

The rock is thrown at an angle isn't it then the initial velocity can be resolved into two components one along the horizontal direction and another along vertical direction right As there is force along the vertical direction (in opposite direction to motion hence decelerates) vertical...

Homework Statement There are two unknown numbers each between 2 & 99 person 'P' is told the product and person 'S' is told the sum when asked about the two numbers their conversation is as follows P-I don't know them S-I knew that already P-Then I know the two numbers P-Then I know...

Hi Hootenanny Sorry for bothering I saw the proof that massless particles should travel at the speed light in another thread. I was just trying to prove it myself thinking wt would happen if we have a massless particle . I think it is wrong.

Thanks for replying I understand massless particles travel at light speed & we cannot have massless particles at rest. but if we just consider we have a massless particle at rest & suppose we apply a small force on it. As massless particle wouldn't oppose being accelerated so its velocity...