- #1
mite
- 23
- 0
For the ground state of a particle moving freely in a one-dimentional box 0[tex]\leq[/tex]x[tex]\leq[/tex]L with rigid reflecting end-points, the uncertainty product (del x)(del p) is
1 h/2
2 sqrt{2}h
3 >h/2
4 h/sqrt{3}
I used (del x)^2 =<x^2>-<x>^2 and (del p)^2 =<p^2>-<p>^2
Using the wavefunction of infinite square well potential in ground state i found the the expectation value . i got
(del x)(del p)= (h/2) ( sqrt{ (1/12) -- (1/2(Pi)^2) } )
which is none of the options.
How to solve it?
1 h/2
2 sqrt{2}h
3 >h/2
4 h/sqrt{3}
I used (del x)^2 =<x^2>-<x>^2 and (del p)^2 =<p^2>-<p>^2
Using the wavefunction of infinite square well potential in ground state i found the the expectation value . i got
(del x)(del p)= (h/2) ( sqrt{ (1/12) -- (1/2(Pi)^2) } )
which is none of the options.
How to solve it?