Recent content by msslowlearner

sorry. I've asked this question again in the HW-CW section. Pls do not reply to this post here.

Homework Statement It is a qualitative problem. No values are given. In an unbalanced Wheatstone Bridge, does the voltage across the resistors R4 and R2 change? In other words is Vr2of balanced bridge=Vr2 of unbalanced bridge? likewse for R4. Homework Equations The Bridge Balance eqn...

In an unbalanced Wheatstone Bridge, does the voltage across the resistors R1 and R2 change? In other words is VR2of balanced bridge=VR2 of unbalanced bridge? I was trying to solve a problem that required qualitative analysis. It says VR2 does not change even though the bridge is unbalanced...

Homework Statement i have the region given as being bounded by x2+y2=4 and z=0 and z=3. this problem asks to prove gauss divergence theorem for a given vector F Homework Equations The Attempt at a Solution As for the volume integral, i had no problem. But for the surface integral, how...

i'm sorry people .. i see it now .. unit normal vector has a length 1 ... personal apologies to "i like serena" .. i kinda questioned ur intelligence.. sorry ... sometimes i miss out the so obvious tiny little things tat matter the most .. sorry guys

oh yes ... v=dr/dt ... it escaped my mind .. i got rxv = w, which is a constant ... so simple .. thanks tiny-tim :)

yes.., I'm new to the physicsforums .. hardly a week here .. :)

yes, but here my value of theta is 154.75 degrees when it should be 25.24 degrees. the only difference being the sign of theta. The magnitude of cos theta is right while the direction is reversed .. where could i have gone wrong ?

the normals as you calculated were right .. maybe the simplification of the cos theta part may have gone wrong ... i proceeded as hallsofvy said in #13, but i got cos theta = -3/sqrt 11

somehow, i don't get it .. i still think it need not be necessarily 1. but since ur a PF contributor, what you say should be right ..i'm just a beginner .. i'll look my concepts again.. thanks for the help :)

sorry .. should have checked the partial derivative part. I thought i got the idea wrong. Its heartening to know I'm on the right track atleast :) thankyou

the magnitude of my vector was 4*rt(11). when i multiply my unit vector with the magnitude, i get my vector again = -4i -12j +4k :) the terms i used to explain may have been obscure,but what i intended to say was tat the unit vector here has a length which is not equal to 1, but it is still...

hang on hang on ! i got it .. simple math.. sqrt(176) = 4*sqrt(11). sorry guys.. my mistake.. thanks for the help :)

yes, the x-component was wrong. now, i get the gradient as -4i -12j +4k whose magnitude is sqrt(176). if the unit normal vector is supposed to be (gradient/magnitude of gradient), i still am not arrivng at the answer !

i don't think it should have length 1. its the vector/mod vector, which is not 1. its the smallest multipliable unit of the vector, when multipled by the length of the vector gives the actual vector .