Show that velocity is perpendicular to rxv

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SUMMARY

The discussion centers on proving that the velocity vector v of a particle, defined by the position vector r = cos(wt) i + sin(wt) j, is perpendicular to the cross product r x v, which is a constant vector. The participants derive the velocity as v = dr/dt = -w sin(wt) i + w cos(wt) j and confirm that r x v = w k, indicating that it is a constant vector in the z-direction. The mathematical definitions and visualizations of vector products are emphasized as essential for understanding the proof.

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  • Understanding of vector calculus, specifically cross products
  • Familiarity with parametric equations and derivatives
  • Knowledge of trigonometric functions and their derivatives
  • Basic concepts of constant vectors in three-dimensional space
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  • Study the properties of vector cross products in three-dimensional space
  • Learn about the geometric interpretation of vector products
  • Explore the application of differential vector calculus in physics
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msslowlearner
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Homework Statement


A particle moves so that its pos. vector is gn by r = cos wt i+sin wt j. show that the velocity v of the particle is perpendicular to and that rxv is a constant vector.

Homework Equations





The Attempt at a Solution



I've tried working this out assuming [B]v[/B] = xi + y j + zk and proceeding with the vector product, but I'm not able to solve for sin wt = 1. (rxv / mod r mod v)
Actually this problem is under the chapter differential vector calculus, but i don't know if perpendicularity can be found usin DVC. Please help.
 
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welcome to pf!

hi msslowlearner! welcome to pf! :wink:

oooh, you're missing the obvious …

v = dr/dt …

so what is dr/dt ? :smile:
 
ah ahhh .. yes, i get it ..the tangent , i.e., the velocity ... how cud i hv missed it ?? anyways, tats the first part .. what about the second ? r x v is a constant vector??
 
how do you say a vector product is constant? i understand that the vector product is the area of the parallelogram formed by the 2 vectors r and v. but how is this constancy represented mathematically ?
 
hi msslowlearner! :smile:

(just got up :zzz: …)
i understand that the vector product is the area of the parallelogram formed by the 2 vectors r and v.

hmm … you're understanding a visualisation of the https://www.physicsforums.com/library.php?do=view_item&itemid=85"

visualisations are there to help you, they are not what the mathematics "really is"

a vector product is mathematics, and to prove things about it, you usually need to use the mathematical definitions, and write out the mathematical equations :wink:
msslowlearner said:
… what about the second ? r x v is a constant vector??
msslowlearner said:
how do you say a vector product is constant? … but how is this constancy represented mathematically ?

you just write out r x v mathematically …

from that, it should be obvious that it's constant

(if something is constant, it usually is obvious! :wink:) …

so what do you get? :smile:
 
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I think when tiny time says "write out r x v mathematically" he means "in terms of the components of r and v".
 
so, here we go..
r x v = (z sin wt)i + (-z cos wt)j+ (y cos wt-x sin wt)k

since rxv is a vector perpendcular to both r and v, v is perpendicular to rxv. right ?? tis one's from the definition itself ...

now, rxv is a fn(t). d/dt (rxv) = zw()r) +yw(-2sin wt)k ... hope I'm right so far... now i assumed that as change in t i.e., del t tends to zero, the k component becomes zero , and
d/dt(rxv=zw (r)

this is what I've arrived at.. how do i say rxv is constant ?
 
hi msslowlearner! :smile:
msslowlearner said:
A particle moves so that its pos. vector is gn by r = cos wt i+sin wt j. show that the velocity v of the particle is perpendicular to and that rxv is a constant vector.

msslowlearner said:
r x v = (z sin wt)i + (-z cos wt)j+ (y cos wt-x sin wt)k

where does this come from?? :confused:

(and what is "z" supposed to be?)

start again …

1) write out r

2) write out v

3) then multiply them …

what do you get for 1) 2) and 3) ? :smile:
 
1) r= cos wt i+sin wtj

2) i assumed v=xi+yj+zk

3) i used the matrix form to calculate r x v = (z sin wt)i + (-z cos wt)j+ (y cos wt-x sin wt)k
 
  • #10
i mean am i getting the cross product atleast correct?? vectors do stump me.
 
  • #11
msslowlearner said:
2) i assumed v=xi+yj+zk

no, use v = dr/dt = … ? :smile:
 
  • #12
oh yes ... v=dr/dt ... it escaped my mind .. i got rxv = w, which is a constant ... so simple .. thanks tiny-tim :)
 
  • #13
Good! What constant did you get? What is r x v?
 
  • #14
HallsofIvy said:
Good! What constant did you get? What is r x v?

he said w ! :wink:

(but he left out the direction)
 
  • #15
msslowlearner said:

Homework Statement


A particle moves so that its pos. vector is gn by r = cos wt i+sin wt j. show that the velocity v of the particle is perpendicular to and that rxv is a constant vector.

Homework Equations





The Attempt at a Solution



I've tried working this out assuming [B]v[/B] = xi + y j + zk and proceeding with the vector product, but I'm not able to solve for sin wt = 1. (rxv / mod r mod v)
Actually this problem is under the chapter differential vector calculus, but i don't know if perpendicularity can be found usin DVC. Please help.




r = cos wt i+sin wt j
dr/dt=v=w (-sin(wt)) i + w (cos(wt)) j

r dot product V = 0

rXv = i j k
cwt swt 0
-wswt -wcwt 0
i j k

cwt swt 0


w cwt cwt k + w swt swt k= w k

rxv = w


and is a constant
 
  • #16
hi stallionx! :smile:

no harm done (since msslowlearner got the answer in post #12),

but pleeease don't give out full answers on this forum! :redface:
 
  • #17
It's probably important to mention that \vec{r}\times\vec{v} = w\hat{k}. That is, it is a vector in the z direction... not just a number.
 
  • #18
tiny-tim said:
hi stallionx! :smile:

no harm done (since msslowlearner got the answer in post #12),

but pleeease don't give out full answers on this forum! :redface:

Hiii, thanks.

I am terribly sorry...
 

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