Show that velocity is perpendicular to rxv

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Homework Help Overview

The problem involves a particle moving with a position vector given by r = cos(wt)i + sin(wt)j. The objective is to demonstrate that the velocity v of the particle is perpendicular to the vector product r x v, and that r x v is a constant vector. The context is within differential vector calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the position vector and velocity, with some attempting to express the velocity as the derivative of the position vector. Questions arise regarding the constancy of the vector product and how to mathematically represent it.

Discussion Status

Some participants have provided guidance on expressing the velocity and the vector product mathematically. There is an ongoing exploration of the implications of the vector product being constant, with various interpretations being considered. However, there is no explicit consensus on the final conclusions.

Contextual Notes

Participants note potential confusion regarding the components of the vectors involved and the assumptions made about the variables. There is also a caution against providing complete solutions, emphasizing the learning process.

msslowlearner
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Homework Statement


A particle moves so that its pos. vector is gn by r = cos wt i+sin wt j. show that the velocity v of the particle is perpendicular to and that rxv is a constant vector.

Homework Equations





The Attempt at a Solution



I've tried working this out assuming [B]v[/B] = xi + y j + zk and proceeding with the vector product, but I'm not able to solve for sin wt = 1. (rxv / mod r mod v)
Actually this problem is under the chapter differential vector calculus, but i don't know if perpendicularity can be found usin DVC. Please help.
 
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welcome to pf!

hi msslowlearner! welcome to pf! :wink:

oooh, you're missing the obvious …

v = dr/dt …

so what is dr/dt ? :smile:
 
ah ahhh .. yes, i get it ..the tangent , i.e., the velocity ... how cud i hv missed it ?? anyways, tats the first part .. what about the second ? r x v is a constant vector??
 
how do you say a vector product is constant? i understand that the vector product is the area of the parallelogram formed by the 2 vectors r and v. but how is this constancy represented mathematically ?
 
hi msslowlearner! :smile:

(just got up :zzz: …)
i understand that the vector product is the area of the parallelogram formed by the 2 vectors r and v.

hmm … you're understanding a visualisation of the https://www.physicsforums.com/library.php?do=view_item&itemid=85"

visualisations are there to help you, they are not what the mathematics "really is"

a vector product is mathematics, and to prove things about it, you usually need to use the mathematical definitions, and write out the mathematical equations :wink:
msslowlearner said:
… what about the second ? r x v is a constant vector??
msslowlearner said:
how do you say a vector product is constant? … but how is this constancy represented mathematically ?

you just write out r x v mathematically …

from that, it should be obvious that it's constant

(if something is constant, it usually is obvious! :wink:) …

so what do you get? :smile:
 
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I think when tiny time says "write out r x v mathematically" he means "in terms of the components of r and v".
 
so, here we go..
r x v = (z sin wt)i + (-z cos wt)j+ (y cos wt-x sin wt)k

since rxv is a vector perpendcular to both r and v, v is perpendicular to rxv. right ?? tis one's from the definition itself ...

now, rxv is a fn(t). d/dt (rxv) = zw()r) +yw(-2sin wt)k ... hope I'm right so far... now i assumed that as change in t i.e., del t tends to zero, the k component becomes zero , and
d/dt(rxv=zw (r)

this is what I've arrived at.. how do i say rxv is constant ?
 
hi msslowlearner! :smile:
msslowlearner said:
A particle moves so that its pos. vector is gn by r = cos wt i+sin wt j. show that the velocity v of the particle is perpendicular to and that rxv is a constant vector.

msslowlearner said:
r x v = (z sin wt)i + (-z cos wt)j+ (y cos wt-x sin wt)k

where does this come from?? :confused:

(and what is "z" supposed to be?)

start again …

1) write out r

2) write out v

3) then multiply them …

what do you get for 1) 2) and 3) ? :smile:
 
1) r= cos wt i+sin wtj

2) i assumed v=xi+yj+zk

3) i used the matrix form to calculate r x v = (z sin wt)i + (-z cos wt)j+ (y cos wt-x sin wt)k
 
  • #10
i mean am i getting the cross product atleast correct?? vectors do stump me.
 
  • #11
msslowlearner said:
2) i assumed v=xi+yj+zk

no, use v = dr/dt = … ? :smile:
 
  • #12
oh yes ... v=dr/dt ... it escaped my mind .. i got rxv = w, which is a constant ... so simple .. thanks tiny-tim :)
 
  • #13
Good! What constant did you get? What is r x v?
 
  • #14
HallsofIvy said:
Good! What constant did you get? What is r x v?

he said w ! :wink:

(but he left out the direction)
 
  • #15
msslowlearner said:

Homework Statement


A particle moves so that its pos. vector is gn by r = cos wt i+sin wt j. show that the velocity v of the particle is perpendicular to and that rxv is a constant vector.

Homework Equations





The Attempt at a Solution



I've tried working this out assuming [B]v[/B] = xi + y j + zk and proceeding with the vector product, but I'm not able to solve for sin wt = 1. (rxv / mod r mod v)
Actually this problem is under the chapter differential vector calculus, but i don't know if perpendicularity can be found usin DVC. Please help.




r = cos wt i+sin wt j
dr/dt=v=w (-sin(wt)) i + w (cos(wt)) j

r dot product V = 0

rXv = i j k
cwt swt 0
-wswt -wcwt 0
i j k

cwt swt 0


w cwt cwt k + w swt swt k= w k

rxv = w


and is a constant
 
  • #16
hi stallionx! :smile:

no harm done (since msslowlearner got the answer in post #12),

but pleeease don't give out full answers on this forum! :redface:
 
  • #17
It's probably important to mention that \vec{r}\times\vec{v} = w\hat{k}. That is, it is a vector in the z direction... not just a number.
 
  • #18
tiny-tim said:
hi stallionx! :smile:

no harm done (since msslowlearner got the answer in post #12),

but pleeease don't give out full answers on this forum! :redface:

Hiii, thanks.

I am terribly sorry...
 

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