What is the angle between the normals to the surface at two given points?

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SUMMARY

The discussion focuses on finding the angle between the normals to the surface defined by the equation xy = z² at the points (1, 4, 2) and (-3, -3, 3). The correct approach involves calculating the gradient of the function F(x, y, z) = xy - z², which yields the normal vectors at the specified points. The angle can then be determined using the dot product of these vectors. The initial attempt at calculating the normals was incorrect, leading to confusion regarding the cosine of the angle.

PREREQUISITES
  • Understanding of gradient vectors and their significance in multivariable calculus.
  • Familiarity with the dot product and its application in calculating angles between vectors.
  • Knowledge of implicit functions and how to derive them from surface equations.
  • Ability to compute partial derivatives for functions of multiple variables.
NEXT STEPS
  • Learn how to compute gradients for implicit functions using the method of Lagrange multipliers.
  • Study the properties of the dot product and its geometric interpretation in vector analysis.
  • Explore the derivation of tangent planes and their relationship to normal vectors in multivariable calculus.
  • Practice solving similar problems involving angles between normals on different surfaces.
USEFUL FOR

Students studying multivariable calculus, particularly those focusing on surface analysis and vector calculus. This discussion is beneficial for anyone looking to deepen their understanding of gradients and normal vectors in three-dimensional space.

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Homework Statement


find the angle between the normals to the surface xy=z2 at the points (1,4,2) and (-3,-3,3)


Homework Equations



none

The Attempt at a Solution


del S = 2zy i + 2zx j
and at the two points, del S = 16i+4j and del S = -18i-18j

using the dot product, i got cos theta = -5/(4*sqrt 34)

which is NOT the answer. Is my partial derivative equation right ? Please help.
 
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msslowlearner said:

Homework Statement


find the angle between the normals to the surface xy=z2 at the points (1,4,2) and (-3,-3,3)


Homework Equations



none

The Attempt at a Solution


del S = 2zy i + 2zx j
and at the two points, del S = 16i+4j and del S = -18i-18j

using the dot product, i got cos theta = -5/(4*sqrt 34)

which is NOT the answer. Is my partial derivative equation right ? Please help.

No, it isn't right. Write f = xy - z2 = 0 and calculate

∇f = <fx,fy,fz>
 
msslowlearner said:

Homework Statement


find the angle between the normals to the surface xy=z2 at the points (1,4,2) and (-3,-3,3)


Homework Equations



none

The Attempt at a Solution


del S = 2zy i + 2zx j
and at the two points, del S = 16i+4j and del S = -18i-18j

using the dot product, i got cos theta = -5/(4*sqrt 34)

which is NOT the answer. Is my partial derivative equation right ? Please help.
It doesn't look right to me. I don't understand how you got what you did.

The equation for your surface is xy = z2, or equivalently, xy - z2 = 0. The implied function here is F(x, y, z) = xy - z2. Your surface is the set of points (x, y, z) for which F(x, y, z) = 0.

For the gradient, calculate \nabla F and evaluate it at the two points. Each will give you a vector. From these vectors you can determine the angle, using the approach that you showed above.
 
sorry .. should have checked the partial derivative part. I thought i got the idea wrong. Its heartening to know I'm on the right track atleast :) thankyou
 
stallionx,

Please don't post complete solutions.

See the rules for posting Homework Help:
"On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given. Under no circumstances should complete solutions be provided to a questioner, whether or not an attempt has been made."

It may still be possible to Edit your post.
 
SammyS said:
stallionx,

Please don't post complete solutions.

See the rules for posting Homework Help:
"On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given. Under no circumstances should complete solutions be provided to a questioner, whether or not an attempt has been made."

I am sorry, Sir.
 
For a tangent plane equation to the z=f(x,y))

z-z0=(delz/delx)(x-x0)+(delz/dely)(y-y0)

which says the normal vector is < delz/delx , delz/dely , -1>

Find those two vectors for 2 different points

Dot product these vectors

V1 * V2 = length(V1)*length(V2) * Cos(theta)

Theta = ACOS ( V1*V2)/ ( product of lengths of perpendicular/ orthogonal vectors )
 
stallionx said:
For a tangent plane equation to the z=f(x,y))

z-z0=(delz/delx)(x-x0)+(delz/dely)(y-y0)

which says the normal vector is < delz/delx , delz/dely , -1>

Find those two vectors for 2 different points

Dot product these vectors

V1 * V2 = length(V1)*length(V2) * Cos(theta)

Theta = ACOS ( V1*V2)/ ( product of lengths of perpendicular/ orthogonal vectors )

DOT PRODUCT can be found from coordinates multiplication and addition

CASE : (x,y,z) dot (a,b,c) is xa+by+cz
 

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