Recent content by mymodded

TL;DR Summary: if there are 2 coils, one with a switch and a battery. If the switch is closed, exactly at that moment when the switch is closed, there is no induced voltage in the other coil, am I correct? In this image, exactly at the moment when we close the switch, there should only be...

I refer to this textbook [PDF link redacted by the Mentors due to Copyright violation] (you can find this lesson on page 274 in the pdf or 267 in the actual book), they don't usually do this, but I feel like they missed out on many pieces of information in this unit. thanks a lot!

Thank you so much appreciate it a lot But wait, ##|v_{R}(t) + v_{L}(t) + v_{C}(t)|^2## is not necessarily always equal to the peak squared while ##V_{R}^2 + (V_{L} - V_{C})^{2}## appears to always equal the peak squared (as it uses the maximum voltage for each component) so how is that so?

there is a question where we had to solve for the inductor's voltage which turned out to be about 500V, even though the AC source was only 12V and the only reason it made sense is because ##V_{m}^{2} =V_{R}^2 + (V_{L} - V_{C})^{2}## and ##V_{C}## was equal to ##V_{L}## (at resonance), so they...

my textbook said this which I don't think is true, tho the textbook still said this (this equation is the true one) so is the textbook right about the first equation?

sorry I think I didn't make my question very clear, I was talking about the polarity of the inductor, that in figure b it should have been positive in the lower side and negative in the upper side, and in my textbook's circuit, that arrow should indicate something about the polarity (even though...

Let's say we have an LC circuit and we begin with the capacitor fully charged, it then starts discharging, and currents begins to flow in the circuit, and a magnetic field is generated in the inductor because of the current flowing through it. My question is, why is the magnetic field in this...

the question is fairly easy to solve, integrating ##NiAB sin(\theta)## from ##\pi## to 0 or just do ##-NiAB(cos(0) - cos(\pi))## which gives you -2NiAB, but my textbook did not include the negative sign, is it mistaken?

thanks a lot really appreciate it

this is the figure in the question.The question can be solved by first finding the induced voltage (and then the induced current), and then we can find the force on each side of the wire due to the magnetic field and subtract them from each other (since the force on the upper and lower sides are...

My textbook solved it by first finding the induced voltage in the inner solenoid but they found it by saying ##-\Delta V_{ind} = A_{2} \frac{d\Phi}{dt}##, but they did not include the number of turns in the solenoid, but I think they should have done that. their final answer is ##\Large...

alright thanks.

No I haven't

Sorry if I'm sounding too dumb, but wouldn't that mean the superpositioned frequency cannot be filtered out since there is only "one" frequency (the superpositioned frequency)?

yes, and even with this, dv/dt is different for each frequency. edit: I mean that since dv/dt is different frequencies, I don't think the capacitor can use dv/dt for each one of them at once.