d/t is not equal to acceleration, that's velocity. In terms of displacement, acceleration is (d^2/dt^2)d. You could also say it's equal to v/t.
There's no need to "convert." The standard units of acceleration are m/s^2. If you work out the units for f/m, it comes out to be m/s^2. You can...
It seems to me that you might be mis-interpreting the question. If your description of the problem is accurate, then it's easy to see that the answer is not 0.33 m/s. If A bumps into B from behind, the speed of both must be faster than the original speed of B. However, if A and B collide...
The mass of the arm would be negligible if the arm's mass was tiny relative to the weight, thus causing a small (negligible) error in your final calculations. Taking the mean value from some data about arm weight found on the internet, a human forearm and hand weigh about 1.5 kg, 50% of the...
First, you find the time it takes for the skier to fall height h (this is independent of the speed of the skier, since the ramp is horizontal). Then, you can find how fast the skier must have been going to travel a distance D in this time.
You can find the velocity at the bottom of the ramp with the information given. You can treat it like a projectile problem, where the skier leaves the ramp at 90 degrees, with an initial height h, and lands a distance D from the ramp. Once you find this velocity, you can use the energy...
You're given the angular velocity (5 rad/sec.) and the radius that the point revolves around (4 cm or .04 m). You just need to plug the values into the centripetal acceleration equation (a=ω2r)
If the net force is 0, that means there is no acceleration (no change in velocity). Whatever initial velocity the object had will be maintained. Presumably, at some point there were imbalanced forces which accelerated the piano to some velocity before the start of the problem.
Your answer...
1300N is not Fnetx. A force of 1300N is applied in the x-direction, and a friction force of 1300N is applied in the negative x-direction. Fnetx is the resultant of these two forces, and since they're equal/opposite forces, the resultant force is 0.
On a distance/time graph, the velocity is the slope of the line. The average velocity between two points on the graph is the slope between the two points.
You don't need to use that information to solve the problem. Since you found one component of the initial velocity (vix), and the problem tells you that the initial velocity is angled at 45°, that's all the information you need. You simply need to calculate the magnitude of the vi vector as I...
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You're doing everything right in the x-dimension, but you also need to consider the y-dimension. You found that since the ball travels 112 feet in the x-direction, its velocity in the x-direction is a constant 28 m/s. I would call the point at 112 feet xf...
It looks alright, but when you take 1/density at the end, the units change to L/g. However, there was no need to use the density equation. Allow me to show you a simpler way:
\displaystyle 1g\: H_2 ×\frac{1\: mole}{2.016 g}=0.5\:mole\: H_2
\displaystyle PV=nRT
\displaystyle V=\frac{nRT}{P}...
Sure there's buoyant force. Have you ever held a rock or something heavy under water? Although it sinks, it still appears lighter. Whenever an object displaces water, there will be a buoyant force on the object. If the metal ball sinks, it's denser than the water, and the mass of displaced...
If the problem states that it's a 1 gram sample of Hydrogen, then the mass is 1 gram. Hydrogen gas is indeed H2, which means each molecule contains two Hydrogen atoms. To account for this, you make a new conversion factor for H2, multiplying the mass of hydrogen by 2.
\displaystyle...