Recent content by nfcfox

Homework Statement This was a test question I had today but basically, initially the mass is at rest as the buoyant force opposes the force of gravity. Then we push it down X meters and let it go. This can be described by SHM. We are also given the density of water, a cross sectional area of...

Hey Simon, thanks for the reply. We managed to figure everything out except we have a last part to the overall project. Essentially we need to find the velocity of a 4 slug mass as it is dropped from the bridge and falls 415 feet below it. This confuses me because the force acting on the mass is...

Homework Statement So this involves a little physics but it is to all be done using calculus (They give us everything we need). Everything is in terms of feet so acceleration due to gravity is 32 ft/(s^2) they tell us the mass of the jumper is 5 slugs. They then tell us that the Force due to...

Right but I guess my question is why is it automatically centered around x=2.

So is the power series already centered about x=2 when I take the derivative??

First four nonzero terms?

Why are you worried about this integral man? I'm worried about sequences and series

He just said he doesn't know what it is, you really think he'd understand that equation? I'm in AP Calc BC which is the calc 2 equivalent and I have never seen anything similar to that equation. You should explain it to him from a calculus 2 standpoint.

Homework Statement http://imgur.com/12LbqWL Part b Homework EquationsThe Attempt at a Solution Since it says the first four terms, not nonzero, the first four terms would be 0-(1/3-0)+2/9(x-2)-1/9(x-2)^2 I'm confused when it says I need to find these for x=2... Do I just plug in x=2 now and...

Homework Statement http://imgur.com/MSkNkno Homework EquationsThe Attempt at a Solution I know that I would have to take the derivative of H(x) which is G(x)+G'(x)x so then I would need G'(x) which I figured would be f'^-1(x) but I'm not sure about that. Doing that I got a value of 16 which...

R3 and R2 as series then that with R1 as parallel.

No this is just something I made on a gizmo. It's part of a problem I am doing.

I already have the answer I found it... I'm just confused as to why adding the 2 10 resistors would then put that in parallel with the last one.

I think the right.

Ok ok I see now. So the resistor on top is added with the one on the right or left then that is put in parallel with the other one... Still kind of weird though because after adding those 2 resistors, wouldn't it not be in parallel after that?