The discussion focuses on calculating the equivalent resistance of a circuit containing three 10-ohm resistors arranged in a combination of series and parallel configurations. Participants emphasize the importance of first combining the two series resistors (R2 and R3) before calculating the equivalent resistance with the remaining resistor (R1) in parallel. The correct approach involves using the formula for series resistors, Req = R1 + R2, and then applying the parallel resistor formula, 1/Req = 1/R + 1/R, to find the total equivalent resistance.
PREREQUISITESStudents in electrical engineering, hobbyists working on circuit design, and anyone looking to improve their understanding of resistor networks and equivalent resistance calculations.
Combine the two series resistors first (what is the equation for combining series resistors?), and then combine the two resulting parallel resistors.nfcfox said:
Isn't there only one series resistor? I'm still not sure how to do this...berkeman said:Combine the two series resistors first (what is the equation for combining series resistors?), and then combine the two resulting parallel resistors.
Ok ok I see now. So the resistor on top is added with the one on the right or left then that is put in parallel with the other one... Still kind of weird though because after adding those 2 resistors, wouldn't it not be in parallel after that?NascentOxygen said:
Right or left? Which one is in series with the resistor on top?nfcfox said:
I think the right.cnh1995 said:
Yes. So what do you get for the answer? Please show your work.nfcfox said:
I already have the answer I found it... I'm just confused as to why adding the 2 10 resistors would then put that in parallel with the last one.berkeman said:Yes. So what do you get for the answer? Please show your work.
No this is just something I made on a gizmo. It's part of a problem I am doing.epenguin said:Was this question meant to test knowledge of resistor colour coding (which I am long unfamiliar with - does it still exist?), the actual calculation being assumed trivial?
Adding the two 10 ohm resistors will give series equivalent resistance Req of them. How are Req and the remaining 10 ohm resistor connected?nfcfox said:
I've added unique identifying labels to the resistors in the figure in post #8. Can you tell us which two resistors you added together and which is the "last one" that you combined with the sum?nfcfox said:
R3 and R2 as series then that with R1 as parallel.gneill said:
I believe that you've misunderstood the problem. It is an entry level problem with three resistors, all 10 Ω. The goal is to reduce the given network to a single equivalent resistance value. It requires the concepts of recognizing series and parallel pairs of resistances and combining said pairs into single values. Eventually a single value representing the entire network's equivalent resistance is achieved.justaman0000 said:
Correct.nfcfox said: