Recent content by NZBRU

I am having problems completing the following questions: a) The answer is apparently in the -y direction (I understand that the direction of propagation is the cross product of the electric and magnetic field that must be perpendicular to each other). I am not sure how to come to this...

Homework Statement So I am trying to accomplish the above by using spherical coordinates, I am aware the problem may be solved using dv=dxdydz= zdxdy were z is known but I would like to try it using a different approach (using spherical coordinates). Any help would be greatly appreciated...

Homework Statement From the derivation of v(x,t) and i(x,t) I am stuck on how the inverse Fourier transform of e^(-jwx/u) was calculated. I am trying to understand how the PDE was fully solved here: http://fourier.eng.hmc.edu/e84/lectures/transmission_line/node1.htmlHomework Equations Not...

I have just realized I have not done the second question correctly which was: A U-shaped tube is partially filled with water. One end of the tube is then capped so that the air in that end is trapped (initially at atmospheric pressure). The tube has a bore diameter of 10mm. The initial height...

I am not familiar with pressure in liquid solutions but I suppose it makes sense that the volume would change if the 1atm gas was sealed as the pressure would change and Pv = NRT meaning v = nRT/P (if the pressure increases then the volume decreases). You could state that the difference is that...

One end of the tube is then capped so that the air in that end is trapped (initially at atmospheric pressure) hmm. That does imply that the pressure on that end will change and not be at an atmospheric pressure meaning the absolute pressure at the other end can not be calculated. I assume when...

Herpaderp, just realized I had to find the ratio of the who heights from v = 2pir^2 for each side. Thanks for the help, I am pretty sure I have that right now. I do apologize for asking another question a similar question has stumped me. Another question states that: A U-shaped tube is...

Thank you for replying :) Well seeing as the narrow section is 5mm wide and the wide section is 50mm wide it could be stated that ten times the volume could fit in the wide section meaning the radio would be- 1n:10w (narrow, wide). So for 500mm 50mm narrow to 450mm wide meaning that the fluid...

Homework Statement The figure shows a schematic drawing of an open ended well-type manometer. Attached to one end of the manometer tube is a well (a reservoir with a higher crossectional area compared to that of the tube). The manometer is filled with a fluid with an SG = 2.95. The manometer...

After reviewing my lecture notes I found that I copied down a different solution. I attempted to redo the problem but came up with this solution, I must of either copied the answer incorrectly or made a mistake in the above working. In regards to reasoning The Torque net must be equal to the...

Homework Statement A ball is released along a horizontal surface with a co-efficient of friction Us at a speed V. Find the time it takes for the ball to start rolling (leave the moment of inertia as I). Homework Equations Quite a few, all of them are stated in my working (that I...

Ep = Ek mgh = Ek mgh = ½mv² v = √2gh As the collision is elastic, m1u1 + m2u2 = m1v1 + m2v2. It is known that m2 = 2m1. m√2gh = 2m1v2 v2 = (m√2gh)/2m v2 = (√2gh)/2 Force body diagram of m2: ̂̂̂̂̂̂Fnet = ma Fnet = Fn + Fg + Ff Fnet = Ff m2a = Ff a = Ff/m2 a = Ff/2m1 a =...

If I typed that in correctly the line would be [-1/A [dp]/[[p - sqrt{(k/A)^2+h} ][p +sqrt {(k/A)^2+h} ]]]=dt or would it be: [-1/A [dp] [p +sqrt {(k/A)^2+h} ]/[p - sqrt{(k/A)^2+h} ]]=dt? (I have not used ASCIIMath extensively). Thank you for the fast response.

Does anyone know how to solve dP/dt = k P - A P2 - h for P. I understand partial fractions are needed and I have already solved dP/dt = k P - A P2. Is anyone able to solve it, Cheers NZBRU.

Oh, that makes sense. My bad, it was lake when I typed that. Is my working for the A and B values correct, I will try to differentiate the final line now.