Recent content by offbeatjumi

thank you! i wasn't sure about where to apply initial conditions

Find the solution of: y" + 3y' = 72sin(3t) + 36cos(3t) where y(0) = 6 and y'(0) = 9 I first found the solution to the homogeneous eq: the roots (R^2 + 3R = 0) are R = 0, -3 which gives the family of solutions: y = a(1) + be^(-3t) and y' = -3be^(-3t) using the initial conditions...

There are two spherical hollow conducting shells, one inside the other. The outer shell has a radius 4 times that of the inner shell. There is a switch connecting the two shells, which is for the moment, open. Both shells have a positive charge (inner shell = +20nC and outer shell = +60nC...

I am missing something very simple... in my book, it gives, for capacitors in series, that: 1/C(eq) = 1/C(1) + 1/C(2) using numbers, it says... 1/C(eq) = 1/6.0 uF + 1/3.0 uF ... C(eq) = 2.0 uF I cannot figure out how they got C(eq) = 2.0 uF Thanks

thanks, muchos =) ill work on it

One definition of work is the change in kinetic energy. I wonder if it is also valid to flip that around and say that if there is a change in kinetic energy... there must have been work done? I assume (could be wrong) that since there are two questions asking about the work done and change in...

So a perpendicular force will only change the direction of linear velocity but not the magnitude. But in this case it will change the angular velocity... I am also asked what the work done is by the cord so to avoid forces... isn't it the same answer to the previous question, the change in...

Homework Statement small block (mass .025 kg) on frictionless horizontal surface is attached to massless cord passing through a hole in the surface. Block is revolving around the hole in the center, with initial angular speed w1 = 1.75 rad/s, 0.3 m away from the hole. The chord is pulled...

Thanks, that was a silly mistake. I feel completely stupid asking this now but i returned to the question and I don't see how I was using moment of inertia to answer my question. It just seems that what I did was solve for ang.accel by taking the change in ang.vel. over change in time to get...

Homework Statement The problem states: grindstone in shape of solid disk with diameter .52m and mass 52 kg rotates at 850 rev/min. You press an ax against the rim with normal force 160 N and grindstone comes to rest in 7.5 s. Find coefficient of friction between ax and grindstone...

so the elastic potential energy of the spring when it is compressed is 0.5(300)(0.15)^2 = 3.375 N*m. So are you saying that the initial kinetic energy of the block 0.5mv^2 = 3.375 ?

Homework Statement A bullet mass(b) .008 kg is fired (and embedded) into a block mass(B) 0.992 kg on a horizontal frictionless surface. The spring is compressed 0.15 m on impact. The spring's constant is 300 N/m. Q: What is the block's velocity after impact Q: What is the initial speed of...

Girl is standing at x = 600m. firecracker 1, at origin, and firecracker 2 at x = 900m, explode simultaneously. the flash from firecracker 1 reach's girls eyes at t = 3.0 microseconds. at what time does she see the flash from firecracker 2? im not even sure the correct way to approach the...

I thought so... But I am really confused now. The values in the problem is that a person is standing at x = 600m. firecracker 1 is at the origin, and firecracker 2 is at x = 900m. the firecrackers explode simultaneously. it is given that the light from firecracker one reaches the person's eyes...

thank you very much yeah i did not assign the correct positions/velocities of the ball to the equation, i see now that the final velocity in the second situation is zero