SIMPLE e&m question: finding equivalent capacitance

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SUMMARY

The equivalent capacitance (C(eq)) for capacitors in series is calculated using the formula 1/C(eq) = 1/C(1) + 1/C(2). In the discussion, the values provided are C(1) = 6.0 µF and C(2) = 3.0 µF. The calculation proceeds as follows: 1/C(eq) = 1/6 + 1/3, which simplifies to 1/6 + 2/6 = 3/6. Therefore, C(eq) is determined to be 2.0 µF after inverting the fraction.

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offbeatjumi
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I am missing something very simple... in my book, it gives, for capacitors in series, that:

1/C(eq) = 1/C(1) + 1/C(2)
using numbers, it says...

1/C(eq) = 1/6.0 uF + 1/3.0 uF ... C(eq) = 2.0 uF

I cannot figure out how they got C(eq) = 2.0 uF

Thanks
 
Last edited:
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1/Ceq = 1/6 + 1/3 --> 1/6 + 2/6 = 3/6

3/6 = 1/2 = 1/ Ceq...

to find Ceq flip --> Ceq = 2uF
 

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