Recent content by offscene

  1. O

    Deriving Maxwell's equations from the Lagrangian

    Thank you so much for your help, I have a question after using the chain rule on the second term. After expanding as you suggested and using the chain rule, I get: =##(\partial_\rho \mathcal{A}_\sigma \eta^{\rho \sigma}) \cdot \eta^{\rho \sigma} \delta_\mu^\rho \delta_\nu^\sigma## but this means...
  2. O

    Deriving Maxwell's equations from the Lagrangian

    This isn't a homework problem (it's an example from David Tong's QFT notes where I didn't understand the steps he took), but I am confused as to how exactly to take the partial derivative of the Lagrangian with respect to ##\partial(\partial_\mu \mathcal{A}_\nu)##. (Note the answer is...
  3. O

    Modifying Euler-Lagrange equation to multivariable function

    I'm confused on how to derive the multidimensional generalization for a multivariable function. Everything makes sense here except the line, $$ \frac{\delta S}{\delta \psi} = \frac{\partial L}{\partial \psi} - \frac{d}{dx} \frac{\partial L}{\partial(\frac{\partial \psi}{\partial x})} -...
  4. O

    Understanding the energy of a dipole in a uniform electric field

    Griffith's E&M problem 4.7 asks to calculate the energy of a dipole in a uniform electric field and I ended up getting a different answer than the one given. I thought that calculating the energy/work done to construct the dipole is the same as dragging two point charges where one is d apart...
  5. O

    Coordinate transformation into a standard flat metric

    Nevermind, I found the transformation with ##x = X\cosh(T)## and ##t = X\sinh(T)## with some guess and check but is there a cleaner way to do this?
  6. O

    Coordinate transformation into a standard flat metric

    I started by expanding ##dx## and ##dt## using chain rule: $$dt = \frac{dt}{dX}dX+\frac{dt}{dT}dT$$ $$dx = \frac{dx}{dX}dX+\frac{dx}{dT}dT$$ and then expressing ##ds^2## as such: $$ds^2 =...
  7. O

    Undergrad Limit of quantum mechanics as h -> 0

    Starting from the Heisenberg equation of motion, we have $$ih \frac{\partial p}{\partial t} = [p, H]$$ which simplifies to $$ih \frac{\partial p}{\partial t} = -ih\frac{\partial V}{\partial x}$$ but this just results in ## \frac{\partial p}{\partial t} = -ih\frac{\partial V}{\partial x}## and...