In reply to your above comment on my post:
Again, it depends on the university and country - I am not sure about the US. Presumably they will only care about your final few years, because these are the exam periods that generally decide whether or not you would be able to handle the degree...
Homework Statement
A spacecraft is protected from the Sun’s radiation by a planar baffle whose size is much greater than that of the spacecraft itself. The baffle is aligned perpendicular to the direction of the Sun. Show that the equilibrium temperature of the baffle is...
What you need to know
Generally, universities in the US and Europe will consider your native qualification and I think that for a Lebanese person these are either the Lebanon baccalaureate (Shahaadat Al-Bakaalouriya al Lubnaaniya l’il-ta ‘liim al-Thaanawi) or the Technical Baccalaureate...
I'm teaching maths to myself so I don't really have anywhere else to go for an explanation other than here, so I apologise if this seems simple.
How do you get from:
(cos^2θ + sin^2θ)(cos^2θ - sin^2θ)
to
cos^4θ - sin^4θ
NOTE: cos^2θ is shorthand for (cosθ)^2 as is with all the...
I'm not sure if this question is something that has been asked before or if i thought about it myself or if it's completely ridiculous!
But I was thinking, if, according to String Theory, particles are 1-dimensional strings that go through modes of oscillation, could they describe how a...
Is there fixed data for the threshold frequency of metals?
For example, is it possible to find out the threshold frequency of iron or copper?
OR
does threshold frequency vary so greatly that with 2 blocks of iron, the theshold frequency could differ between them?
Depending on the...
Besides, that's not even an answer to my question!
I asked for each mathematical step and all you give me is $$x^-1/2=√\frac{1}{x}$$
So come on, what's each mathematical step?
One would assume that:
$$t \propto h^\alpha m^\beta g^\gamma$$
Where t = time taken for object to fall, h = height dropped from, m = mass, g = acceleration due to gravity.
By doing some dimensional analysis one can find that:
$$t \propto h^\frac{1}{2} g^\frac{-1}{2}$$ and that t is...