Recent content by onyxorca
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Solving Air Hockey Collision: Puck A & B Speeds
y is 0 so .016*(.016*7.91)tan65+.032*x*tan37=0 ? .18/cos37=.225 for b?- onyxorca
- Post #3
- Forum: Introductory Physics Homework Help
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Solving Air Hockey Collision: Puck A & B Speeds
Homework Statement The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0160 kg and is moving along the x-axis with a velocity of +7.91 m/s. It makes a collision with puck B, which has a mass of 0.0320 kg and is initially at rest. The collision is not...- onyxorca
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- Air Collision
- Replies: 2
- Forum: Introductory Physics Homework Help
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How Is Kinetic Friction Calculated in Skier's Uphill Motion?
Correct! thank you!- onyxorca
- Post #4
- Forum: Introductory Physics Homework Help
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How Is Kinetic Friction Calculated in Skier's Uphill Motion?
Homework Statement A 64.9-kg skier coasts up a snow-covered hill that makes an angle of 23.4 ° with the horizontal. The initial speed of the skier is 8.95 m/s. After coasting a distance of 2.31 m up the slope, the speed of the skier is 4.40 m/s. (a) Find the work done by the kinetic frictional...- onyxorca
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- Force Frictional force Kinetic Kinetic frictional force
- Replies: 4
- Forum: Introductory Physics Homework Help
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Centripetal force on a top down loop
Fn=Fc-Fg Fn=mv^2/r-mg 300=mv^2/r-950 mv^2/r=300+950 v=sqrt((300+950)r/m) =15.2350 m/s ?- onyxorca
- Post #3
- Forum: Introductory Physics Homework Help
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Centripetal force on a top down loop
Homework Statement A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and...- onyxorca
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- Centripetal Centripetal force Force Loop
- Replies: 5
- Forum: Introductory Physics Homework Help
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Solving for Lunar Landing Craft Thrust
well the numbers in the problem changes every time so i wouldn't know if this is right but i got the right answer for that time. in this case though it's probably F = 8.73E3 (1.6+.627304) = 19444.4 N because it's Fg-Fthrust, not the other way around.- onyxorca
- Post #13
- Forum: Introductory Physics Homework Help
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Solving for Lunar Landing Craft Thrust
V0=V^2+2ax find a F=mg-ma=m(g-a) i finally got it right, had trouble realizing that the thrust is smaller than gravitational force and i made mistakes when putting in the scientific digits but i finally got it.- onyxorca
- Post #11
- Forum: Introductory Physics Homework Help
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Solving for Lunar Landing Craft Thrust
well appearantly 8491 isn't right...- onyxorca
- Post #9
- Forum: Introductory Physics Homework Help
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Skier on a slope (Fnormal, Ffriction, etc)
or was it u times normal force? 61.4*9.8cos30.9*.116=59.8925 N?- onyxorca
- Post #2
- Forum: Introductory Physics Homework Help
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Solving for Lunar Landing Craft Thrust
Fthrust - Fg = ma? so F - 8730*1.6 = 8730*-0.627304 F=8491.64 N?- onyxorca
- Post #6
- Forum: Introductory Physics Homework Help
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Solving for Lunar Landing Craft Thrust
F=ma the forces are gravity and thrust. btw the mass is 8.73 × 10^3 kg. the acceleration is 0=16.5^2+2a217 and a = -0.627304 m/s^2 ? where do i go from there?- onyxorca
- Post #4
- Forum: Introductory Physics Homework Help
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Skier on a slope (Fnormal, Ffriction, etc)
Homework Statement A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 30.9 ° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 61.4 kg, and the coefficient of kinetic friction...- onyxorca
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- Slope
- Replies: 1
- Forum: Introductory Physics Homework Help
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Solving for Lunar Landing Craft Thrust
Homework Statement A 8.73 × 103-kg lunar landing craft is about to touch down on the surface of the moon, where the acceleration due to gravity is 1.60 m/s2. At an altitude of 217 m the craft's downward velocity is 16.5 m/s. To slow down the craft, a retrorocket is firing to provide an...- onyxorca
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- Lunar Thrust
- Replies: 13
- Forum: Introductory Physics Homework Help
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Magnitude of the maximum gravitational force
but that's the minus sign from the formula isn't it?- onyxorca
- Post #3
- Forum: Introductory Physics Homework Help