Magnitude of the maximum gravitational force

AI Thread Summary
The discussion centers on calculating the maximum gravitational force between a bowling ball and a billiard ball using the formula F = -Gm1m2/r^2. The calculated force is approximately -7.44 × 10^-9 N, but the negative sign is debated since the magnitude should be expressed as a positive value. Participants clarify that the formula typically omits the negative sign when discussing magnitude. The focus remains on ensuring the correct interpretation of gravitational force in terms of magnitude. The final takeaway emphasizes that the gravitational force should be reported as a positive value.
onyxorca
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Homework Statement



A bowling ball (mass = 5.9 kg, radius = 0.11 m) and a billiard ball (mass = 0.36 kg, radius = 0.028 m) may each be treated as uniform spheres. What is the magnitude of the maximum gravitational force that each can exert on the other?

Homework Equations



F=-Gm1m2/r^2

The Attempt at a Solution



6.67*10^-11*5.9*.36/-(.11+.028)^2 = -7.43913043 × 10^-9 N

right?
 
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Right. altough I don't think the minus sign is right.
 
but that's the minus sign from the formula isn't it?
 
onyxorca said:
but that's the minus sign from the formula isn't it?

The formula is usually given without a minus sign. The question also asks for the magnitude of the force, which has to be positive.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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