Skier on a slope (Fnormal, Ffriction, etc)

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SUMMARY

The discussion focuses on calculating the force exerted by a tow bar on a skier being pulled up a slope inclined at 30.9° with a mass of 61.4 kg and a coefficient of kinetic friction of 0.116. The correct approach involves using the equation for frictional force, Ff = uN, where N is the normal force. The normal force is determined by the skier's weight component perpendicular to the slope, leading to the calculation of the tow bar force as approximately 59.89 N.

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Homework Statement



A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 30.9 ° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 61.4 kg, and the coefficient of kinetic friction between the skis and the snow is 0.116. Find the magnitude of the force that the tow bar exerts on the skier.

Homework Equations



Ff=uN

The Attempt at a Solution



so is it the tow bar force = force of friction? the answer is just u times horizontal component of gravitational force?
 
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or was it u times normal force? 61.4*9.8cos30.9*.116=59.8925 N?
 

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