Solving Air Hockey Collision: Puck A & B Speeds

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The discussion focuses on a collision between two air hockey pucks, where puck A, with a mass of 0.0160 kg and a velocity of +7.91 m/s, collides with stationary puck B, which has a mass of 0.0320 kg. Participants are analyzing the conservation of momentum in both x and y components to determine the speeds of puck A and puck B after the collision. The key point is that momentum is conserved separately in both directions, and the initial momentum in the y-direction is zero. The calculations involve using trigonometric functions to relate the angles of deflection to the velocities of the pucks post-collision. Understanding these principles is essential for solving the problem accurately.
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Homework Statement



The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0160 kg and is moving along the x-axis with a velocity of +7.91 m/s. It makes a collision with puck B, which has a mass of 0.0320 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

http://edugen.wiley.com/edugen/courses/crs2216/art/qb/qu/c07/ch07p_30.gif

Homework Equations



p=mv

The Attempt at a Solution



is it the y-components are equal to each other or the x-component?

.016*7.91*sin65=.032*x*sin37 ?
 
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onyxorca said:

Homework Statement



The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0160 kg and is moving along the x-axis with a velocity of +7.91 m/s. It makes a collision with puck B, which has a mass of 0.0320 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

http://edugen.wiley.com/edugen/courses/crs2216/art/qb/qu/c07/ch07p_30.gif

Homework Equations



p=mv

The Attempt at a Solution



is it the y-components are equal to each other or the x-component?

.016*7.91*sin65=.032*x*sin37 ?

The components of the momentum in the x and y directions are separately conserved. Which component of the system's momentum is zero before the collision? Whenyou figure this out, you will be able to answer your question.
 
y is 0

so
.016*(.016*7.91)tan65+.032*x*tan37=0 ?

.18/cos37=.225 for b?
 

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