Solving Air Hockey Collision: Puck A & B Speeds

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SUMMARY

The discussion focuses on solving a collision problem involving two air hockey pucks, where puck A (0.0160 kg) moves at +7.91 m/s and collides with stationary puck B (0.0320 kg). The conservation of momentum in both x and y directions is crucial for determining the final speeds of both pucks post-collision. The participants confirm that the momentum components in the x-direction are conserved, while the y-components are initially zero. The final calculations yield the speeds of puck A and puck B based on their respective angles after the collision.

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Homework Statement



The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0160 kg and is moving along the x-axis with a velocity of +7.91 m/s. It makes a collision with puck B, which has a mass of 0.0320 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

http://edugen.wiley.com/edugen/courses/crs2216/art/qb/qu/c07/ch07p_30.gif

Homework Equations



p=mv

The Attempt at a Solution



is it the y-components are equal to each other or the x-component?

.016*7.91*sin65=.032*x*sin37 ?
 
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onyxorca said:

Homework Statement



The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0160 kg and is moving along the x-axis with a velocity of +7.91 m/s. It makes a collision with puck B, which has a mass of 0.0320 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

http://edugen.wiley.com/edugen/courses/crs2216/art/qb/qu/c07/ch07p_30.gif

Homework Equations



p=mv

The Attempt at a Solution



is it the y-components are equal to each other or the x-component?

.016*7.91*sin65=.032*x*sin37 ?

The components of the momentum in the x and y directions are separately conserved. Which component of the system's momentum is zero before the collision? Whenyou figure this out, you will be able to answer your question.
 
y is 0

so
.016*(.016*7.91)tan65+.032*x*tan37=0 ?

.18/cos37=.225 for b?
 

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