Recent content by patelneel1994

625 m^2/s^2 = 2gy - 4/3 gy y = 96 m Thanks for detailed explanation. wonderful BvU

To find the velocity = delta x/ delta t

It's +9.8 m/s2. So second equation would be V(t) = V(o) + at? V(t) = 25m/s + 9.8 m/s2 2/3 y?

100 m came from 20 m/s . 5 s

is it Xt = X0 + V0 . t + 1/2 . a .t^2?

I meant to say garvity = g. Could you tell me what else I need to get the maximum height.

So 60 m = -20m/s . t + 1/2 a t2 60 m = -20m/s t - 4.9 m/s2 t2? What should I do after this ...

Homework Statement The position of a particle as it moves along the x-axis is given by x = 15e-2t m, where t is in s. What is the acceleration of the particle at t = 1 s? Homework Equations d = vi.t + 1/2 a ts since I don't know how distance is implemented. The Attempt at a...

Can we apply this law? Velocity is positive direction and if the velocity increases with time, then acceleration is said to be positive. In this case, if the velocity is reducing with time, then the acceleration said to be negative

Homework Statement An object moving on the x-axis with a constant acceleration increases its x coordinate by 80 m in a time of 5.0 s and has a velocity of +20 m/s at the end of this time. Determine the acceleration of the object during this motion. x = 80m t = 5.0 second v = + 20m/s a = while...

Homework Statement An object is thrown vertically upward such that it has a speed of 25 m/s when it reaches two thirds of its maximum height above the launch point. Determine this maximum height. Homework Equations Vf^2 = Vi^2 +2gt The Attempt at a Solution Couldn't figure out Vi...

Homework Statement A stone is thrown from the top of a building with an initial velocity of 20 m/s downward. The top of the building is 60 m above the ground. How much time elapses between the instant of release and the instant of impact with the ground? Vi = -20 m/s height = 60 m t = ...

I got 41 m. Thanks

So instead of d I should put h. Find height for each object separately!

Homework Statement An object is thrown downward with an initial (t = 0) speed of 10 m/s from a height of 60 m above the ground. At the same instant (t = 0), a second object is propelled vertically upward from ground level with a speed of 40 m/s. At what height above the ground will the two...