At what height objects will pass each other?

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Homework Help Overview

The problem involves two objects: one thrown downward from a height of 60 m with an initial speed of 10 m/s, and another propelled upward from ground level with a speed of 40 m/s. The goal is to determine the height at which the two objects will pass each other.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of height variables for each object and the need to account for their different starting heights. There is a suggestion to express the height in terms of a single variable.

Discussion Status

Some participants have provided numerical results for the height at which the objects meet, but there is no explicit consensus on the method used to arrive at those results. The discussion includes various interpretations of the problem setup and the equations involved.

Contextual Notes

Participants are navigating the constraints of the problem, including the initial conditions and the differing starting heights of the objects. There is an emphasis on ensuring consistent variable usage throughout the discussion.

patelneel1994
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Homework Statement



An object is thrown downward with an initial (t = 0) speed of 10 m/s from a height of 60 m above the ground. At the same instant (t = 0), a second object is propelled vertically upward from ground level with a speed of 40 m/s. At what height above the ground will the two objects pass each other?

first object
t0 = 0
V = 10 m/s
H = 60
Second object
t0 = 0
V = 40 m/s
H = 60

Homework Equations


d = Vi . t + 1/2 a t2


The Attempt at a Solution


This equation doesn't see me to work since we need to find at which height objects will pass
 
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hi patelneel1994! :wink:

call the height of either object above the ground "d", and rememb
er that the two objects start at different values of d …

show us what you get :smile:
 
So instead of d I should put h. Find height for each object separately!
 
d or h, it doesn't matter, so long as you use the same symbol for each, but start them at different values :wink:
 
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I got 41 m. Thanks
 
patelneel1994 said:
I got 41 m. Thanks
I confirm that answer. A slightly quicker way, perhaps, is to note that the two objects undergo the same acceleration, so the relative velocity is constant. The closing speed is therefore a constant 10+40=50 m/s. That tells you how long they take to meet.
 
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