Recent content by Phoenixtears
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Hyperbolic Geometry: Parameterization of Curves for Hyperbolic Distance
Okay, I feel a little silly for not understanding his parameterization, but I do understand it now. My question then moves to if there is a quick trick to parameterizing potentially more difficult curves in the hyperbolic plane?- Phoenixtears
- Post #2
- Forum: Calculus and Beyond Homework Help
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Hyperbolic Geometry: Parameterization of Curves for Hyperbolic Distance
Homework Statement Consider the points P = (1/2, √3/2) and Q = (1,1). They lie on the half circle of radius one centered at (1,0). a) Use the deifnition and properites of the hyperbolic distance (and length) to compute dH(P,Q). b) Compute the coordinates of the images of Pa nd Q...- Phoenixtears
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- Curves Geometry Hyperbolic
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Undergrad Modern Algebra: Permutations and Cycles
Ah, that makes perfect sense to me. Thank you so much! The examples we did in class involved specific cycle structures for alpha to gamma, and I didn't quite understand how those came to be. What does the inverse of a permutation represent, then, if there is no specific cycle structure?- Phoenixtears
- Post #3
- Forum: Linear and Abstract Algebra
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Undergrad Modern Algebra: Permutations and Cycles
Hi there, I'm doing homework right now (no this isn't a homework question!) and have basic questions on permutations and cycles. The concept seemed so simple in class and still seems simple, but the notation using lowercase Greek letters is confusing me. Do η and \theta and most of the...- Phoenixtears
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- Algebra Cycles Permutations
- Replies: 3
- Forum: Linear and Abstract Algebra
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Understanding Magnification in Lens Systems
I was merely using the wrong distance. Thanks though. :) Oh, and I just copy and pasted the entire question. That is how it's worded. The image just wouldn't appear. ~Phoenix- Phoenixtears
- Post #5
- Forum: Introductory Physics Homework Help
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Understanding Magnification in Lens Systems
I managed to find a diagram that was basically the same idea (ignoring the already drawn ray lines). Essentially, the left side length is 11cm and the right of the lens is 49.5 cm as I found. All my explanation says is I plugged my numbers into the equation for magnification and it didn't work...- Phoenixtears
- Post #3
- Forum: Introductory Physics Homework Help
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Understanding Magnification in Lens Systems
GREEN= Correct Homework Statement The lens in the figure is used to produce a real image of a candle flame at the 36 cm mark. What is the focal length of the lens? focal length= 9 (My attachments aren't working, however, if you were to draw a line, put a lens in the middle, then a...- Phoenixtears
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- Magnification
- Replies: 4
- Forum: Introductory Physics Homework Help
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How Is Energy Conserved in a Photon-Electron Collision?
Homework Statement An incident photon having a frequency of 2.00 E10^19 Hz collides with an electron initially at rest. What is the total energy of the two-particle system after the collision? (In joules The Attempt at a Solution I've stared at this problem for at least an hour an...- Phoenixtears
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- Collision Electron Photon
- Replies: 1
- Forum: Introductory Physics Homework Help
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Power Dissipation in Resistors: P31.52
Thanks for the hints. This is where I'm at now: I used P=V^2/R to get the voltage of the bottom resistor: 21.91. Then, using that number and the equation P=IV I found the current: 2.19 That current is constant throughout the system. I then used the equation V=IR to find the voltage...- Phoenixtears
- Post #5
- Forum: Introductory Physics Homework Help
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Power Dissipation in Resistors: P31.52
There are multiple equations I was given in class, two are: P=IV and V=IR. But how does P=IV help me if it doesn't include resistance. I can't seem to figure out a way to include the two equations for it to work for the first part of the problem. I do realize that I can substitute I out to make...- Phoenixtears
- Post #3
- Forum: Introductory Physics Homework Help
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Power Dissipation in Resistors: P31.52
Homework Statement Consider the circuit in Figure P31.52, in which R = 10 . The 10 resistor is dissipating 48 W of power. How much power are the other two resistors dissipating? (Image Attached) 5 resistor ________ 20 resistor ___24___ Homework Equations VI=RP The...- Phoenixtears
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- Power Resistor
- Replies: 5
- Forum: Introductory Physics Homework Help
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Calculate Value of Resistor R in Ex31.21 | ΔV = 5.0V, I = 62mA
Actually, this is the first time I've really used resistance in this manner at all. I didn't know about a 'total resistance' and the fact that each small section holds a separate resistance that adds up to the total resistance. And I'm not in physics to remember tricks. I want to understand the...- Phoenixtears
- Post #6
- Forum: Introductory Physics Homework Help
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Calculate Value of Resistor R in Ex31.21 | ΔV = 5.0V, I = 62mA
*Sigh* Thank you so much, both of you! Figures I'd forget something so simple. Now I'll never forget that... hopefully. Thank you!- Phoenixtears
- Post #4
- Forum: Introductory Physics Homework Help
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Calculate Value of Resistor R in Ex31.21 | ΔV = 5.0V, I = 62mA
[SIZE="5"]SOLVED Homework Statement What is the value of resistor R in Figure Ex31.21, in which ΔV = 5.0 V and I = 62 mA? (Image Attached) Homework Equations RI=V The Attempt at a Solution My attempt at the solution is literally solely the equation above. I can't see any...- Phoenixtears
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- Resistor Value
- Replies: 6
- Forum: Introductory Physics Homework Help
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Velocity of a Proton in a Capacitor
Aha! I see. That makes so much more sense. Becasue the field is down, the acceleration is also down. Then the horizonatal acceleration is 0 (I should have listened to my sister :-P). Thank you so much!- Phoenixtears
- Post #3
- Forum: Introductory Physics Homework Help