okay so completing the square gives me
y = x^2 +8x + 20 + 16 - 16
y = (x^2 + 8x +16) + 4
then factor...
y = (x + 4)^2 + 4
which is exactly what I got before?
Change the equation to standard form.
y = x^2 + 8x + 20
I thought this was the standard form for parabolas?? I tried this as the answer but it said it was wrong
y = (x+4)^2 +4
Thanks for the help! :-)
[SOLVED] More trig substitution help...
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****************
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V...
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