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Help with Volume circular disk.

  1. Jan 22, 2008 #1
    Consider the solid S described below.
    The base of S is a circular disk with radius 3r. Parallel cross-sections perpendicular to the base are squares.
    Find the volume V of this solid.


    I tried this....


    A(x) = pi*r^2 = pi*(3r)^2 = pi*9r^2

    V(x) = integral from 0 to 3r(pi*9r^2 dx) = pi*27r^3


    Am I approaching this problem the wrong way? Thanks for the help!
     
  2. jcsd
  3. Jan 22, 2008 #2

    dynamicsolo

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    The square cross-sections are built upon the circular base, so each cross-section has a side length given by the length of a chord of the circle; these "slices" are standing upright on the circle. (Making a picture of this will be helpful to you.) The solid is symmetric about a diameter of the circle, so you can integrate half the solid and multiply your result by two.

    So what you need is to find the length of a chord of the circle which has its midpoint at a distance x from the circle's center. That length gives you the area A(x) of each cross-section. You would then integrate A(x) from x = 0 to x = 3r and multiply the resulting volume by 2.
     
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