My mistake, I did use the diameter/ 2 in my calculations ( just translated it incorrectly) so I still had the same calculation. Is there something else I am missing?
[b]1. [b]1. An air-core solenoid with 57 turns is 4.96 cm
long and has a diameter of 1.46 cm.
The permitivity of free space is 4×10−7 T·
m/A.
How much energy is stored in its magnetic
field when it carries a current of 0.634 A ?
Answer in units of μJ.
[b]2.
B = mu-o (I) (N)/ L...
[b]1. An air-core solenoid with 57 turns is 4.96 cm
long and has a diameter of 1.46 cm.
The permitivity of free space is 4×10−7 T·
m/A.
How much energy is stored in its magnetic
field when it carries a current of 0.634 A ?
Answer in units of μJ.
[b]2.
B = mu-o (I) (N)/ L
Induction=...
So would I be able to solve equations 3 and 4 somehow to find mass and velocity? Those are my two unknowns. I need velocity to solve for mass.
Is there another relationship I am missing to help me solve for velocity?
[b]1. A 1.56024 μC charged particle with a kinetic
energy of 0.115905 J is placed in a uniform
magnetic field of magnitude 0.150267 T.
If the particle moves in a circular path of
radius 3.13685 m, find its mass. Answer in
units of kg.
Homework Equations
Fe= Fm
Fe= qE
KE=mv^2/2
Fm=...
[b]1. A 1.56024 μC charged particle with a kinetic
energy of 0.115905 J is placed in a uniform
magnetic field of magnitude 0.150267 T.
If the particle moves in a circular path of
radius 3.13685 m, find its mass. Answer in
units of kg.
Homework Equations
Fe= Fm
Fe= qE
KE=mv^2/2
Fm=...
[b]1. A singly charged positive ion has a mass = 1.08e-26 kg
After being accelerated through a potential difference of 240 V the ion enters a magnetic field of 0.595 T in a direction perpendicular to the field.
The charge on the ion is 1.602 e-19 C.
Find the radius of the ion's path in the...
[b]1. A singly charged positive ion has a mass = 1.08e-26 kg
After being accelerated through a potential difference of 240 V the ion enters a magnetic field of 0.595 T in a direction perpendicular to the field.
The charge on the ion is 1.602 e-19 C.
Find the radius of the ion's path in the...
]1. A 1.3 cm length of tungsten filament in a small lightbulb has a resistance of 0.032 ohms. Find its diameter.
Given: Length= 1.3 cm= .013m
R= 0.032 ohms
resistivity= 5.6e-8 ohms*meter
[b]2.
A= pi (r^2)
R= resistivity (Length/ Area)
The Attempt at a Solution
R= resistivity...
[b]1. A 1.3 cm length of tungsten filament in a small lightbulb has a resistance of 0.032 ohms. Find its diameter.
Given: Length= 1.3 cm= .013m
R= 0.032 ohms
resistivity= 5.6e-8 ohms*meter
[b]2.
A= pi (r^2)
R= resistivity (Length/ Area)
The Attempt at a Solution
R=...