What Is the Diameter of a Tungsten Filament with a Given Length and Resistance?

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Homework Help Overview

The discussion centers around determining the diameter of a tungsten filament given its length and resistance. The problem involves concepts from electrical resistance and material properties, specifically focusing on the relationship between resistivity, length, and cross-sectional area.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the formula for resistance in terms of resistivity and area, but encounters an issue with unit conversion when calculating the diameter in millimeters.
  • Some participants suggest reconsidering the unit conversion process, specifically the multiplication factor when converting from meters to millimeters.
  • Others emphasize the importance of maintaining units throughout the calculations to avoid errors.

Discussion Status

Participants are actively engaging with the problem, providing insights on unit conversion and the significance of dimensional analysis. There is no explicit consensus on the resolution of the original poster's confusion, but guidance on unit handling has been offered.

Contextual Notes

The problem is framed within the constraints of a homework assignment, which may impose specific requirements for the final answer format. The original poster's calculations and assumptions are under scrutiny, particularly regarding the conversion of units.

rinarez7
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1. A 1.3 cm length of tungsten filament in a small lightbulb has a resistance of 0.032 ohms. Find its diameter.
Given: Length= 1.3 cm= .013m
R= 0.032 ohms
resistivity= 5.6e-8 ohms*meter



2.
A= pi (r^2)
R= resistivity (Length/ Area)



The Attempt at a Solution


R= resistivity ( Length/ pi* (r^2) )
.032 ohms= (5.6e-8 ohms*meter) * (.o13m/ (pi* (r^2)) )
.032 (pi) (r^2) = 7.28e-10
.100530965 (r^2) = 7.28e-10
r= 8.509e-5
diameter= 2r= 1.701e-4m

It asks for the answer in mm, so I divided my answer by 1000= 1.7 e-7 mm, but it's not correct = (
What am I missing?
Thanks in advance!
 
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Try multplying your answer by a 1000?
If you have an answer in m, the answer in mm is going to a be BIGGER number
 
What makes Physics physical are the units. Units are as essential to the solution procedure as the mathematical expressions used to determine its quantities. Therefore, units must accompany their magnitudes throughout. In fact, this will often help as a conincident double check on the answer. Tables of Fundamental Units can be found in many books.
In your problem to convert your answer, already in meters, into millimeters, you recall that multiplying by one (1) doesn't change much.
Since 1 meter = 1,000 millimeters, you could divide one side by the other to arrive at the same answer: 1. In order to have millimeters appear in your answer then, you would multiply your answer in meters by 1,000 millimeters/1 meter (i.e. 1). As you can see the meters cancel out leaving the units in millimeters.
You could multiply it by 1 meter/1,000 millimeters also 1, but then you have to consider you've expressed the diameter, a linear measurement in terms of
10 e-3 meters^2/millimeters an unorthodox form but frankly not incorrect.
 
Last edited:
Of course that "1,000" factor has to multiply your numerical answer since you have just multiplied your meters by "milli".
 

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