Recent content by sith
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Graduate Clever coordinate substitution for linear PDE
Yes, it was actually the method that I used to solve it (before I knew there was a name for the method =P). The substitution $$r(\phi, v) = A\left(\frac{1}{3}v^3 - v_r^2 v\right) - B\sin(\phi)$$ is the characteristic of the ##\phi, v##-differential equation.- sith
- Post #6
- Forum: Differential Equations
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Graduate Clever coordinate substitution for linear PDE
Ah, yes, I see that.. =P But I think I actually have found a way to solve the problem. First to separate out the time dependence as you suggested. Then use the coordinate substitution ##r(\phi, v)## as I wrote in the first post, and simply put ##s(\phi, v) = v##. Then of course ##B\cos(\phi)##...- sith
- Post #4
- Forum: Differential Equations
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Graduate Clever coordinate substitution for linear PDE
Sorry, I forgort to mention also that v_r is constant.- sith
- Post #2
- Forum: Differential Equations
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Graduate Clever coordinate substitution for linear PDE
Hi! I am currently working with a linear PDE on the form \frac{\partial f}{\partial t} + A(v^2 - v_r^2)\frac{\partial f}{\partial \phi} + B\cos(\phi)\frac{\partial f}{\partial v} = 0. A and B are constants. I wish to find a clever coordinate substitution that simplifies, or maybe even...- sith
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- Coordinate Linear Pde Substitution
- Replies: 5
- Forum: Differential Equations
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Graduate Change of variables in a second order SDE
I have made some progress in the work. Treating H as constant \sigma_v can be found to be \sigma_v = \frac{\pi A R}{\sqrt{t_c}(v - v_r)}\cos(n\phi - \phi_w) by using Itô's lemma on the more simple form d v = \frac{d v}{d\phi}d\phi + \frac{1}{2}\frac{d^2 v}{d\phi^2}d[\phi,\phi]. I...- sith
- Post #2
- Forum: Differential Equations
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Graduate Change of variables in a second order SDE
Hello everyone! I am fairly new to SDE theory, so I'm sorry if my question may be a bit naive. I have the following coupled set of SDE:s d\phi = \frac{v - v_r}{R}d t + \frac{\pi}{\sqrt{t_c}}d W d v = A\cos(n\phi - \phi_w)d t + a_v d t + \sigma_v d W. W denotes a Wiener process, and the...- sith
- Thread
- Change Change of variables Second order Variables
- Replies: 1
- Forum: Differential Equations
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Graduate Nonlinear system of differential equations
Oh, this is really great! Thanks everyone for your help :D- sith
- Post #5
- Forum: Differential Equations
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Graduate Nonlinear system of differential equations
Hi! I'm working with my PhD thesis at the moment, and I've stumbled upon a pretty involved problem. What I have is a system of equations like this: \frac{dx}{dt} = A \cos(z) \frac{dy}{dt} = B x \frac{dx}{dt} \frac{dz}{dt} = y where A and B are constants. I also have a stochastic term to z...- sith
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- Differential Differential equations Nonlinear System
- Replies: 4
- Forum: Differential Equations
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Transmission Coefficient for two step potential
The velocity of the wave affects the probability flux of the wave. The transmission probability is properly defined as the ratio of the probability flux of the transmitted and the incident wave. In the potential step case the transmission probability is then T =...- sith
- Post #3
- Forum: Advanced Physics Homework Help
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Graduate How to define the b.c.s for the EM field of a perfectly contucting surface?
If you have a 3 dimensional perfectly conducting body the conditions at the boundary for the EM field is as follows: \boldsymbol{E}_{\parallel} = 0, B_{\perp} = 0, E_{\perp} = \frac{\sigma}{\epsilon_0}, \boldsymbol{B}_{\parallel} = \mu_0 \boldsymbol{j} \times \boldsymbol{\hat{n}} where \sigma...- sith
- Thread
- Em Field Surface
- Replies: 1
- Forum: Electromagnetism
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Graduate Definition of time-ordered product for Dirac spinors
Sorry, I found what I did wrong in the derivations, and now I get it out right with the A definition. :)- sith
- Post #2
- Forum: Quantum Physics
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Graduate Definition of time-ordered product for Dirac spinors
I guess the answer to this question actually should be pretty obvious, but I still have problems getting it right though. I wonder about the definition of the time ordered product for a pair of Dirac spinors. In all the books I've read it simply says: T\left\{\psi(x)\bar{\psi}(x')\right\} =...- sith
- Thread
- Definition Dirac Product Spinors
- Replies: 1
- Forum: Quantum Physics
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Construction of an equivalent dielectric tensor
Btw, is it possible that you also take T. Hellsten's course at KTH and have this exercise as a deadline until next thursday? Just wondering. :)- sith
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Construction of an equivalent dielectric tensor
Hi! I actually did this one just a moment ago. I guess you are also solving exercise 6.1 in Melrose, McPhedran's book "Electromagnetic processes in dispersive media". :) You should use the following equations: K_{i,j}(\omega, \textbf{k}) = \delta_{ij} + \frac{i}{\omega...- sith
- Post #2
- Forum: Engineering and Comp Sci Homework Help