Construction of an equivalent dielectric tensor

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SUMMARY

The discussion focuses on constructing the equivalent dielectric tensor {K_{ij}}(\omega, \textbf{k}) using the response functions \varepsilon(\omega) and {\mu^{-1}}(\omega). The key equations provided include K_{i,j}(\omega, \textbf{k}) = \delta_{ij} + \frac{i}{\omega \epsilon_0}\sigma_{ij}(\omega, \textbf{k}) and \textbf{D} = \varepsilon(\omega)\textbf{E}. Participants reference Melrose and McPhedran's book "Electromagnetic Processes in Dispersive Media" as a resource for solving the problem. The discussion emphasizes the relationship between electric displacement, polarization, and magnetic fields in dispersive media.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically Maxwell's equations.
  • Familiarity with dielectric materials and their response functions.
  • Knowledge of tensor notation and operations in physics.
  • Experience with complex analysis in the context of wave propagation.
NEXT STEPS
  • Study the derivation of the equivalent dielectric tensor in dispersive media.
  • Learn about the physical significance of the polarization vector \textbf{P} and magnetization vector \textbf{M}.
  • Explore the application of the equations in practical scenarios, such as wave propagation in anisotropic materials.
  • Review the concepts presented in "Electromagnetic Processes in Dispersive Media" by Melrose and McPhedran for deeper insights.
USEFUL FOR

Students and researchers in physics, particularly those focusing on electromagnetism, material science, and wave propagation in complex media.

billybomb87
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Homework Statement



A medium is described by the response functions \varepsilon (\omega ) and {\mu ^{ - 1}}(\omega ) in

\textbf{D} = \varepsilon (\omega )\textbf{E}, \textbf{H} = {\mu ^{ - 1}}(\omega )\textbf{B}.

Construct the equivalent dielectric tensor {K_{ij}}(\omega ,\textbf{k}) in terms of \varepsilon (\omega ) and {\mu ^{ - 1}}(\omega )

Homework Equations



\textbf{D} = \varepsilon (\omega )\textbf{E}

\textbf{H} = {\mu ^{ - 1}}(\omega )\textbf{B}

\textbf{P} = {\varepsilon _0}{\chi ^e}\textbf{E}

\textbf{M} = {\chi ^m}\textbf{B}/{\mu _0}

{P_i} = {\varepsilon _0}\chi _{ij}^e{E_j}

{M_i} = \chi _{ij}^m{B_j}/{\mu _0}

The Attempt at a Solution



I seriously have no idea. I know what the answer should be but I only need a push in the right direction. Dont know where to start or how to attack the problem. All help is appreciated.
 
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Hi! I actually did this one just a moment ago. I guess you are also solving exercise 6.1 in Melrose, McPhedran's book "Electromagnetic processes in dispersive media". :) You should use the following equations:

<br /> K_{i,j}(\omega, \textbf{k}) = \delta_{ij} + \frac{i}{\omega \epsilon_0}\sigma_{ij}(\omega, \textbf{k})

<br /> \left(\textbf{J}_{ind}\right)_i(\omega, \textbf{k}) = \sigma_{ij}(\omega, \textbf{k})E_j(\omega, \textbf{k})

<br /> \left(\textbf{J}_{ind}\right)_i(\omega, \textbf{k}) = -i\omega P_i(\omega, \textbf{k}) + i \epsilon_{ijk}k_j M_k(\omega, \textbf{k})

<br /> P_i(\omega, \textbf{k}) = D_i(\omega, \textbf{k}) - \epsilon_0 E_i(\omega, \textbf{k})

<br /> D_i(\omega, \textbf{k}) = \epsilon(\omega)E_i(\omega, \textbf{k})

<br /> M_i(\omega, \textbf{k}) = \frac{1}{\mu_0}B_i(\omega, \textbf{k}) - H_i(\omega, \textbf{k})

<br /> H_i(\omega, \textbf{k}) = \mu^{-1}(\omega)B_i(\omega, \textbf{k})

<br /> B_i(\omega, \textbf{k}) = \frac{1}{\omega}\epsilon_{ijk}k_j E_k(\omega, \textbf{k})

Then I guess the rest is straightforward. Good luck!
 
Btw, is it possible that you also take T. Hellsten's course at KTH and have this exercise as a deadline until next thursday? Just wondering. :)
 

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