Recent content by six7th

Thanks, I wrongly assumed the constants would be 0 because the object started at rest and I didn't think to check my result matched the initial conditions! Ok, so after finding the constant I get: x(t) = \frac{mc^2}{F}\sqrt{1+(\frac{Ft}{mc})^2} - \frac{mc^2}{F} =...

Sorry I accidentally clicked post before I finished typing everything up. The main post has been updated with how far I've got.

Homework Statement a) A mass m starts at rest. Starting at t = 0 (measured in the lab frame), you apply a constant force f to it (lab frame). How long (in the lab frame) does it take for the mass to move a distance x (also measured in the lab frame)? Check that your answer makes sense in the...

Ok I see that this is true if the two events are one shot being fired and another being fired. So I now have: Δt = γΔt' = γ\frac{l'}{u'} The distance traveled by a bullet in the ground frame is therefore: uΔt = uγ\frac{l'}{u'} Using the velocity addition formula this gives uΔt =...

It's my understanding that Δx' is the distance between events in the train frame which is surely l', meaning the transformation is not simply γΔt'?

Homework Statement A train moves at speed v. Bullets are successively fired at speed u (relative to the train) from the back of the train to the front. A new bullet is fired at the instant (as measured in the train frame) the previous bullet hits the front. In the frame of the ground, what...

I see it now, thank you! The radius of the segment is just simple trigonometry, r = R\sinθ So the area now becomes: A = πR^2 \sin^2θ

For a normal loop of wire, A would be the area inside the loop so in this case dA is the area bounded by the surface, da, of the thin segment. I have tried using the volume of the segments but the equation for magnetic moments requires an area, so I couldn't see how this would work. Edit: I...

Homework Statement Show for a solid spherical ball of mass m rotating through its centre with a charge q uniformly distributed on the surface of the ball that the magnetic moment μ is related to the angular momentum L by the relation: \textbf{μ} = \frac{5q}{6mc}\textbf{L}Homework Equations μ...

Yeah I am binning the data, here's a basic outline of what is being done: Generate 1 Million values from a Gaussian distribution of mean 0 and standard deviation 1 Add gaussian noise to each of these values, we now have two distributions of numbers. One with noise and one without Sort by the...

The way I have used the notation is that A and B are the distributions and x and y are the numbers that belong to each distribution. Thanks chiro. Surely if I generate an arbitrary but finite amount of numbers from a Gaussian distribution then I will have a new distribution of numbers which...

Suppose I have a Gaussian probability distribution: N_{A}(0,1). A set of values are generated from this distribution to which an arbitrary amount of Gaussian noise, say N_{B}(0,0.5), is added and then the N_{B} values sorted from lowest to highest. These are then digitised by assigning 0...

Homework Statement I'm currently writing a program that will read in a list of gaussian distributed random numbers as an array and will make a 'measurement', that is they will be assigned to another array with an associated error. This is to try and simulate the communication of Alice to Bob...

Hi all, I've just finished my 2nd year of a 4 year course (MPhys) at a UK Russell Group University studying physics, and I'm feeling a little disheartened. In September I will be on exchange at McGill in Montreal for a year and upon looking at the problem sets and the lecture notes of courses...