Recent content by sonrie

Thanks!

Finally Got it! Thanks

Can someone help me? need help!

The diagram looks like: http://i283.photobucket.com/albums/kk298/elias2933/YF-26-06.jpg

For the circuit both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.25 . What does the voltmeter read? What is the emf of the battery? I tried this: 15 ohm and 10 ohm resistors are in series, hence equivalent to 25 ohm. Three...

nevermind i got it.

What is the period T of the wave ? If i am given: Maximum electric field of 2450 V/m Wavelength of 547 nm I found: Angular Wave # 1.15*10^7 Angular Frequency 3.45*10^15 Velocity of Electromagnetic Wave 3*10^8 m/s B max of 8.17*10^-6 T Intensity of 7960 W/m^2 I tried to solve...

A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has radius 12.5 cm , and the outer sphere has radius 16.5 cm . A potential difference of 100 V is applied to the capacitor. What is the energy density at r = 12.6 cm , just outside...

when there hooked up together the volt reads 50, when dielectric is put in volts reads 11.5 so a difference of 38.5 Volts. Does this have anything to do to get the answer?

your Right! so my equation will be 1.05*10^-9= 8.85*10^-12*3.70*A/2.95*10^-4 . I finally got it RIGHT! Thank You So Much! Have a GREAT DAY!

Thank you!

the equation is emf = -N BA/T -240 5.9*10^-5*.137/5.9*10^-5=3.28*10^-9 its still wrong

shouldn't it be 7.7 because when the dielectric is completely fills the space it reads 11.5 so then if we pull 1/3 of it out then 2/3 is still fills the space so 11.5/3=3.83, 3.83 *2= 7.7. I know its wrong but is my assumption wrong as well?

With the formula that you provided by equation will look like this: 1.05*10^-9= 8.85*10^-12 *3.70* A / 2.94*10^10 so i just solve for A? then my final answer would be final answer was 9.47*10^-11 still wrong

sorry its 2.94 *10^10